Lösung 1.2:1a
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
K (Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel)) |
K (hat „Solution 1.2:1a“ nach „Lösung 1.2:1a“ verschoben: Robot: moved page) |
Version vom 13:25, 22. Okt. 2008
In order for fractions to be added together, they need first to be rewritten so that they have the same denominator, and we do this by multiplying the numerator and denominator of each fraction by the denominator of the other fraction. So,
\displaystyle \frac{7\cdot 7}{4\cdot 7}+\frac{11\cdot 4}{7\cdot 4}=\frac{49}{28}+\frac{44}{28}\,. |
Now, the numerators can be added together,
\displaystyle \frac{49}{28}+\frac{44}{28}=\frac{49+44}{28}=\frac{93}{28}\,. |