Lösung 4.2:1f

Aus Online Mathematik Brückenkurs 1

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If we write the tangent for the angle, this gives a relation which contains ''x'' as the only unknown,
If we write the tangent for the angle, this gives a relation which contains ''x'' as the only unknown,
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{{Displayed math||<math>\tan 50^{\circ} = \frac{19}{x}\,\textrm{.}</math>}}
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{{Abgesetzte Formel||<math>\tan 50^{\circ} = \frac{19}{x}\,\textrm{.}</math>}}
This gives
This gives
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{{Displayed math||<math>x=\frac{19}{\tan 50^{\circ }}\quad ({}\approx 15\textrm{.}9)\,\textrm{.}</math>}}
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{{Abgesetzte Formel||<math>x=\frac{19}{\tan 50^{\circ }}\quad ({}\approx 15\textrm{.}9)\,\textrm{.}</math>}}

Version vom 08:50, 22. Okt. 2008

The side adjacent to the angle of 50° is marked x and the opposite is the side of length 19.

If we write the tangent for the angle, this gives a relation which contains x as the only unknown,

\displaystyle \tan 50^{\circ} = \frac{19}{x}\,\textrm{.}

This gives

\displaystyle x=\frac{19}{\tan 50^{\circ }}\quad ({}\approx 15\textrm{.}9)\,\textrm{.}
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_4.2:1f“