Lösung 4.2:1d

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By writing the quotient for <math>\cos 20^{\circ}</math>, we obtain the relation
By writing the quotient for <math>\cos 20^{\circ}</math>, we obtain the relation
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{{Displayed math||<math>\cos 20^{\circ} = \frac{16}{x}</math>}}
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{{Abgesetzte Formel||<math>\cos 20^{\circ} = \frac{16}{x}</math>}}
and this gives
and this gives
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{{Displayed math||<math>x = \frac{16}{\cos20^{\circ}}\quad ({}\approx 17\textrm{.}0)\,\textrm{.}</math>}}
+
{{Abgesetzte Formel||<math>x = \frac{16}{\cos20^{\circ}}\quad ({}\approx 17\textrm{.}0)\,\textrm{.}</math>}}

Version vom 08:50, 22. Okt. 2008

The side marked x is the hypotenuse in the right-angled triangle and the side of length 16 is the adjacent to the angle of 20°.

By writing the quotient for \displaystyle \cos 20^{\circ}, we obtain the relation

\displaystyle \cos 20^{\circ} = \frac{16}{x}

and this gives

\displaystyle x = \frac{16}{\cos20^{\circ}}\quad ({}\approx 17\textrm{.}0)\,\textrm{.}
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_4.2:1d“