Lösung 3.3:2h
Aus Online Mathematik Brückenkurs 1
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The argument in the logarithm can be rewritten as <math>\frac{1}{10^{2}} = 10^{-2}</math> and then the log law <math>\lg a^b = b\lg a</math> gives the rest | The argument in the logarithm can be rewritten as <math>\frac{1}{10^{2}} = 10^{-2}</math> and then the log law <math>\lg a^b = b\lg a</math> gives the rest | ||
| - | {{ | + | {{Abgesetzte Formel||<math>\lg \frac{1}{10^2} = \lg 10^{-2} = (-2)\cdot \lg 10 = (-2)\cdot 1 = -2\,\textrm{.}</math>}} |
Version vom 08:42, 22. Okt. 2008
The argument in the logarithm can be rewritten as \displaystyle \frac{1}{10^{2}} = 10^{-2} and then the log law \displaystyle \lg a^b = b\lg a gives the rest
| \displaystyle \lg \frac{1}{10^2} = \lg 10^{-2} = (-2)\cdot \lg 10 = (-2)\cdot 1 = -2\,\textrm{.} |
