Lösung 3.3:2c

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Because <math>\mathop{\text{lg}} 0\textrm{.}001</math> is defined as the exponent that should stand in the coloured box in the equality
Because <math>\mathop{\text{lg}} 0\textrm{.}001</math> is defined as the exponent that should stand in the coloured box in the equality
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{{Displayed math||<math>10^{\bbox[#FFEEAA;,1.5pt]{\phantom{\scriptstyle ??}}} = 0\textrm{.}001</math>}}
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{{Abgesetzte Formel||<math>10^{\bbox[#FFEEAA;,1.5pt]{\phantom{\scriptstyle ??}}} = 0\textrm{.}001</math>}}
and we have that
and we have that
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{{Displayed math||<math>10^{-3} = 0\textrm{.}001\,,</math>}}
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{{Abgesetzte Formel||<math>10^{-3} = 0\textrm{.}001\,,</math>}}
thus <math>\mathop{\text{lg}} 0\textrm{.}0001 = -3\,</math>.
thus <math>\mathop{\text{lg}} 0\textrm{.}0001 = -3\,</math>.

Version vom 08:41, 22. Okt. 2008

Because \displaystyle \mathop{\text{lg}} 0\textrm{.}001 is defined as the exponent that should stand in the coloured box in the equality

\displaystyle 10^{\bbox[#FFEEAA;,1.5pt]{\phantom{\scriptstyle ??}}} = 0\textrm{.}001

and we have that

\displaystyle 10^{-3} = 0\textrm{.}001\,,

thus \displaystyle \mathop{\text{lg}} 0\textrm{.}0001 = -3\,.

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_3.3:2c“