Processing Math: Done
To print higher-resolution math symbols, click the
Hi-Res Fonts for Printing button on the jsMath control panel.
No jsMath TeX fonts found -- using image fonts instead.
These may be slow and might not print well.
Use the jsMath control panel to get additional information.
jsMath Control PanelHide this Message

jsMath

Lösung 2.1:2c

Aus Online Mathematik Brückenkurs 1

(Unterschied zwischen Versionen)
Wechseln zu: Navigation, Suche
K
K (Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel))
Zeile 1: Zeile 1:
We obtain the answer by using the squaring rule, <math>(a+b)^2=a^2+2ab+b^2,</math> on the quadratic term and expanding the other bracketed terms
We obtain the answer by using the squaring rule, <math>(a+b)^2=a^2+2ab+b^2,</math> on the quadratic term and expanding the other bracketed terms
-
{{Displayed math||<math>\begin{align}
+
{{Abgesetzte Formel||<math>\begin{align}
(3x+4)^2&-(3x-2)(3x-8)\\
(3x+4)^2&-(3x-2)(3x-8)\\
&=\big( (3x)^2+2\cdot 3x \cdot 4 +4^2 \big) - (3x\cdot 3x-3x\cdot 8 - 2\cdot 3x+ 2\cdot 8)\\
&=\big( (3x)^2+2\cdot 3x \cdot 4 +4^2 \big) - (3x\cdot 3x-3x\cdot 8 - 2\cdot 3x+ 2\cdot 8)\\

Version vom 08:21, 22. Okt. 2008

We obtain the answer by using the squaring rule, (a+b)2=a2+2ab+b2 on the quadratic term and expanding the other bracketed terms

(3x+4)2−(3x−2)(3x−8)=(3x)2+23x4+42−(3x3x−3x8−23x+28)=(9x2+24x+16)−(9x2−24x−6x+16)=(9x2+24x+16)−(9x2−30x+16)=(9x2+24x+16)−9x2+30x−16=9x2−9x2+24x+30x+16−16=0+54x+0=54x.
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_2.1:2c“