Lösung 1.3:5c
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
			  			                                                      
		          
			| K  | K  (Robot: Automated text replacement  (-{{Displayed math +{{Abgesetzte Formel)) | ||
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| We can write <math>9 = 3\cdot 3 = 3^{2}</math> and then the power rules give | We can write <math>9 = 3\cdot 3 = 3^{2}</math> and then the power rules give | ||
| - | {{ | + | {{Abgesetzte Formel||<math>9^{\frac{3}{2}} = \bigl(3^{2}\bigr)^{\frac{3}{2}} = 3^{2\cdot \frac{3}{2}} = 3^{3} = 3\cdot 3\cdot 3 = 27\,</math>.}} | 
Version vom 08:18, 22. Okt. 2008
We can write \displaystyle 9 = 3\cdot 3 = 3^{2} and then the power rules give
| \displaystyle 9^{\frac{3}{2}} = \bigl(3^{2}\bigr)^{\frac{3}{2}} = 3^{2\cdot \frac{3}{2}} = 3^{3} = 3\cdot 3\cdot 3 = 27\,. | 
 
		  