Lösung 1.3:3e

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The number 9 can be written as <math>9=3\cdot 3=3^{2}</math> and hence the denominator in the expression is equal to
The number 9 can be written as <math>9=3\cdot 3=3^{2}</math> and hence the denominator in the expression is equal to
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{{Displayed math||<math>9^{2} = (3^{2})^{2} = 3^{2\cdot 2} = 3^{4}\,</math>.}}
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{{Abgesetzte Formel||<math>9^{2} = (3^{2})^{2} = 3^{2\cdot 2} = 3^{4}\,</math>.}}
The whole quotient becomes
The whole quotient becomes
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{{Displayed math||<math>\frac{3}{9^{2}}=\frac{3^{1}}{3^{4}}=3^{1-4}=3^{^{-3}}</math>.}}
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{{Abgesetzte Formel||<math>\frac{3}{9^{2}}=\frac{3^{1}}{3^{4}}=3^{1-4}=3^{^{-3}}</math>.}}

Version vom 08:17, 22. Okt. 2008

The number 9 can be written as \displaystyle 9=3\cdot 3=3^{2} and hence the denominator in the expression is equal to

\displaystyle 9^{2} = (3^{2})^{2} = 3^{2\cdot 2} = 3^{4}\,.

The whole quotient becomes

\displaystyle \frac{3}{9^{2}}=\frac{3^{1}}{3^{4}}=3^{1-4}=3^{^{-3}}.
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_1.3:3e“