Lösung 1.2:1c

Aus Online Mathematik Brückenkurs 1

(Unterschied zwischen Versionen)
Wechseln zu: Navigation, Suche
K
K (Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel))
Zeile 1: Zeile 1:
We multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator,
We multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator,
-
{{Displayed math||<math>\frac{1}{6}-\frac{2}{5}=\frac{1\cdot 5}{6\cdot 5}-\frac{2\cdot 6}{5\cdot 6}=\frac{5}{30}-\frac{12}{30}\,</math>.}}
+
{{Abgesetzte Formel||<math>\frac{1}{6}-\frac{2}{5}=\frac{1\cdot 5}{6\cdot 5}-\frac{2\cdot 6}{5\cdot 6}=\frac{5}{30}-\frac{12}{30}\,</math>.}}
Then the numerators can be subtracted
Then the numerators can be subtracted
-
{{Displayed math||<math>\frac{5}{30}-\frac{12}{30}=\frac{5-12}{30}=\frac{-7}{30}=-\frac{7}{30}\,</math>.}}
+
{{Abgesetzte Formel||<math>\frac{5}{30}-\frac{12}{30}=\frac{5-12}{30}=\frac{-7}{30}=-\frac{7}{30}\,</math>.}}

Version vom 08:13, 22. Okt. 2008

We multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator,

\displaystyle \frac{1}{6}-\frac{2}{5}=\frac{1\cdot 5}{6\cdot 5}-\frac{2\cdot 6}{5\cdot 6}=\frac{5}{30}-\frac{12}{30}\,.

Then the numerators can be subtracted

\displaystyle \frac{5}{30}-\frac{12}{30}=\frac{5-12}{30}=\frac{-7}{30}=-\frac{7}{30}\,.
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_1.2:1c“