Lösung 3.3:6a
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
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- | The calculator does not have button for | + | The calculator does not have button for <math>\log_{3}</math>, but it does have one for the natural logarithm ln, so we need to rewrite <math>\log_{3}4</math> in terms of ln. |
- | <math>\ | + | |
- | <math>\ | + | |
- | in terms of ln. | + | |
- | If we go back to the definition of the logarithm, we see that | + | If we go back to the definition of the logarithm, we see that <math>\log _{3}4</math> is that number which satisfies |
- | <math>\log _{3}4</math> | + | |
- | is that number which satisfies | + | |
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+ | {{Displayed math||<math>3^{\log _{3}4} = 4\,\textrm{.}</math>}} | ||
Now, take the natural logarithm of both sides, | Now, take the natural logarithm of both sides, | ||
+ | {{Displayed math||<math>\ln 3^{\log _{3}4}=\ln 4\,\textrm{.}</math>}} | ||
- | + | Using the logarithm law, <math>\lg a^b = b\lg a</math>, the left-hand side can be written as <math>\log_{3}4\cdot\ln 3</math> and the relation is | |
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- | Using the logarithm law, | + | |
- | <math>\lg a^ | + | |
- | <math>\ | + | |
- | and the relation is | + | |
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+ | {{Displayed math||<math>\log_{3}4\cdot \ln 3 = \ln 4\,\textrm{.}</math>}} | ||
- | <math> | + | Thus, after dividing by <math>\ln 3</math>, we have |
+ | {{Displayed math||<math>\log_{3}4 = \frac{\ln 4}{\ln 3} = \frac{1\textrm{.}386294\,\ldots}{1\textrm{.}098612\,\ldots} = 1\textrm{.}2618595\,\ldots</math>}} | ||
which gives 1.262 as the rounded-off answer. | which gives 1.262 as the rounded-off answer. | ||
- | NOTE: on a calculator, the answer is obtained by pressing the buttons | ||
+ | Note: On the calculator, the answer is obtained by pressing the buttons | ||
- | < | + | <center> |
+ | {| | ||
+ | || | ||
+ | {| border="1" cellpadding="3" cellspacing="0" | ||
+ | |width="30px" align="center"|4 | ||
+ | |} | ||
+ | || | ||
+ | || | ||
+ | {| border="1" cellpadding="3" cellspacing="0" | ||
+ | |width="30px" align="center"|LN | ||
+ | |} | ||
+ | || | ||
+ | || | ||
+ | {| border="1" cellpadding="3" cellspacing="0" | ||
+ | |width="30px" align="center"|÷ | ||
+ | |} | ||
+ | || | ||
+ | || | ||
+ | {| border="1" cellpadding="3" cellspacing="0" | ||
+ | |width="30px" align="center"|3 | ||
+ | |} | ||
+ | || | ||
+ | || | ||
+ | {| border="1" cellpadding="3" cellspacing="0" | ||
+ | |width="30px" align="center"|LN | ||
+ | |} | ||
+ | || | ||
+ | || | ||
+ | {| border="1" cellpadding="3" cellspacing="0" | ||
+ | |width="30px" align="center"|= | ||
+ | |} | ||
+ | |} | ||
+ | </center> |
Version vom 07:53, 2. Okt. 2008
The calculator does not have button for \displaystyle \log_{3}, but it does have one for the natural logarithm ln, so we need to rewrite \displaystyle \log_{3}4 in terms of ln.
If we go back to the definition of the logarithm, we see that \displaystyle \log _{3}4 is that number which satisfies
Now, take the natural logarithm of both sides,
Using the logarithm law, \displaystyle \lg a^b = b\lg a, the left-hand side can be written as \displaystyle \log_{3}4\cdot\ln 3 and the relation is
Thus, after dividing by \displaystyle \ln 3, we have
which gives 1.262 as the rounded-off answer.
Note: On the calculator, the answer is obtained by pressing the buttons
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