Lösung 3.3:1d

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Exactly as in exercise c, we write the left-hand side as
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Exactly as in exercise c, we write the left-hand side as <math>10^{-x}</math>, and the right-hand side as <math>0\textrm{.}0001 = 10^{-4}</math>, i.e. <math>10^{-x} = 10^{-4}</math>, which gives <math>x=4\,</math>.
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<math>\text{1}0^{-x}</math>, and the right-hand side as
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<math>0.000\text{1}=\text{1}0^{-4}</math>, i.e.
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<math>\text{1}0^{-x}=\text{1}0^{-4}</math>, which gives
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<math>x=\text{4}</math>.
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Version vom 14:19, 1. Okt. 2008

Exactly as in exercise c, we write the left-hand side as \displaystyle 10^{-x}, and the right-hand side as \displaystyle 0\textrm{.}0001 = 10^{-4}, i.e. \displaystyle 10^{-x} = 10^{-4}, which gives \displaystyle x=4\,.

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_3.3:1d“