Lösung 3.3:1c

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We can write the left-hand side as
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We can write the left-hand side as <math>10^{-x}</math> and this should be equal to <math>100 = 10^2</math>; thus, we see that ''x'' must equal -2.
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<math>\text{1}0^{-x}</math>
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and this should be equal to
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<math>\text{1}00=\text{1}0^{\text{2}}</math>; thus, we see that
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<math>x\text{ }</math>
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must equal
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<math>-\text{2}</math>.
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Version vom 14:17, 1. Okt. 2008

We can write the left-hand side as \displaystyle 10^{-x} and this should be equal to \displaystyle 100 = 10^2; thus, we see that x must equal -2.

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_3.3:1c“