Lösung 2.3:5b
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
			  			                                                      
		          
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| - | Instead of randomly trying different values of  | + | Instead of randomly trying different values of ''x'', it is better investigate the second-degree expression by completing the square, | 
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| - | , it is better investigate the second-degree expression by completing the square | + | |
| + | {{Displayed math||<math>\begin{align} | ||
| + | 4x^{2} - 28x + 48 | ||
| + | &= 4(x^{2} - 7x + 12)\\[5pt] | ||
| + | &= 4\bigl((x-\tfrac{7}{2})^{2} - (\tfrac{7}{2})^{2} + 12\bigr)\\[5pt]  | ||
| + | &= 4\bigl((x-\tfrac{7}{2})^{2} - \tfrac{49}{4} + \tfrac{48}{4}\bigr)\\[5pt] | ||
| + | &= 4\bigl((x-\tfrac{7}{2})^{2} - \tfrac{1}{4}\bigr)\\[5pt] | ||
| + | &= 4\bigl(x - \tfrac{7}{2}\bigr)^{2}-1\,\textrm{.} | ||
| + | \end{align}</math>}} | ||
| - | <math> | + | In the expression in which the square has been completed, we see that if, e.g. | 
| - | + | <math>x=7/2</math>, then the whole expression is negative and equal to -1. | |
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| - | + | Note: All values of ''x'' between 3 and 4 give a negative value for the expression. | |
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Version vom 11:10, 29. Sep. 2008
Instead of randomly trying different values of x, it is better investigate the second-degree expression by completing the square,
In the expression in which the square has been completed, we see that if, e.g. \displaystyle x=7/2, then the whole expression is negative and equal to -1.
Note: All values of x between 3 and 4 give a negative value for the expression.
 
		  