Lösung 4.3:2a

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On a unit circle, the angle
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<center> [[Image:4_3_2_a.gif]] </center>
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<math>{3\pi }/{2}\;</math>
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corresponds to the point
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<math>\left( 0 \right.,\left. -1 \right)</math>, and the angle in the interval from
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<math>0</math>
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to
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<math>\pi </math>
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which has the same cosine value as
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<math>{3\pi }/{2}\;</math>, i.e. the x-coordinate
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<math>0</math>, is the angle
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<math>v={\pi }/{2}\;</math>.
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<center> [[Image:4_3_2a.gif]] </center>
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<center> [[Image:4_3_2_a.gif]] </center>

Version vom 10:25, 29. Sep. 2008

On a unit circle, the angle \displaystyle {3\pi }/{2}\; corresponds to the point \displaystyle \left( 0 \right.,\left. -1 \right), and the angle in the interval from \displaystyle 0 to \displaystyle \pi which has the same cosine value as \displaystyle {3\pi }/{2}\;, i.e. the x-coordinate \displaystyle 0, is the angle \displaystyle v={\pi }/{2}\;.


Image:4_3_2_a.gif
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_4.3:2a“