Lösung 3.3:4a

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Individually, the terms are difficult to calculate, but the two logarithms can be lumped together using the logarithm law,
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<math>\text{log }a-\text{ log }b=\text{log}\left( \frac{a}{b} \right)</math>,
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<math>\lg 50-\lg 5=\lg \frac{50}{5}=\lg 10=1.</math>

Version vom 14:46, 25. Sep. 2008

Individually, the terms are difficult to calculate, but the two logarithms can be lumped together using the logarithm law, \displaystyle \text{log }a-\text{ log }b=\text{log}\left( \frac{a}{b} \right),


\displaystyle \lg 50-\lg 5=\lg \frac{50}{5}=\lg 10=1.

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_3.3:4a“