Lösung 3.3:2e

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From the definition of logarithm base
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<math>\text{1}0</math>, we see directly that
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<math>\text{1}0^{\text{lg}\,\text{2}}=\text{2}</math>.

Version vom 13:16, 25. Sep. 2008

From the definition of logarithm base \displaystyle \text{1}0, we see directly that \displaystyle \text{1}0^{\text{lg}\,\text{2}}=\text{2}.

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_3.3:2e“