Lösung 2.2:8c

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By moving the term in
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By moving the term in ''x'' over to the right-hand side and dividing by 3, the inequality can be rewritten as
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<math>x</math>
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over to the right-hand side and dividing by
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<math>3</math>, the inequality can be rewritten as
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{{Displayed math||<math>y\le 2-\frac{2}{3}x\,\textrm{.}</math>}}
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<math>y\le 2-\frac{2}{3}x</math>.
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Then, we see that the area that we should shade consists of all the points under the straight line <math>y=2-\tfrac{2}{3}x\,</math>.
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Then, we see that the area that we should shade consists of all the points under the straight line
 
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<math>y=2-\frac{2}{3}x</math>.
 
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{{NAVCONTENT_START}}
 
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{{NAVCONTENT_STOP}}
 
[[Image:2_2_8_c.gif|center]]
[[Image:2_2_8_c.gif|center]]

Version vom 13:46, 24. Sep. 2008

By moving the term in x over to the right-hand side and dividing by 3, the inequality can be rewritten as

Vorlage:Displayed math

Then, we see that the area that we should shade consists of all the points under the straight line \displaystyle y=2-\tfrac{2}{3}x\,.


Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_2.2:8c“