Lösung 2.1:8c
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
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- | When we come across large and complicated expressions, we have to work step by step; | + | When we come across large and complicated expressions, we have to work step by step; as a first goal, we can multiply the top and bottom of the fraction |
- | + | {{Displayed math||<math>\frac{1}{1+\dfrac{1}{1+x}}</math>}} | |
+ | by <math>1+x</math>, so as to reduce it to an expression having one fraction sign | ||
- | + | {{Displayed math||<math>\begin{align} | |
- | + | \frac{1}{1+\dfrac{1}{1+\dfrac{1}{1+x}}} | |
- | + | &= \frac{1}{1+\dfrac{1}{1+\dfrac{1}{1+x}}\cdot\dfrac{1+x}{1+x}}\\[8pt] | |
- | + | &= \frac{1}{1+\dfrac{1+x}{\Bigl(1+\dfrac{1}{1+x}\Bigr)(1+x)}}\\[8pt] | |
- | + | &= \frac{1}{1+\dfrac{1+x}{1+x+\dfrac{1+x}{1+x}}}\\[8pt] | |
- | + | &= \frac{1}{1+\dfrac{1+x}{1+x+1}}\\[8pt] | |
- | + | &= \frac{1}{1+\dfrac{x+1}{x+2}}\,\textrm{.} | |
- | <math>\begin{align} | + | \end{align}</math>}} |
- | + | ||
- | + | ||
- | & =\frac{1}{1+\ | + | |
- | \end{align}</math> | + | |
- | + | ||
The next step is to multiply the top and bottom of our new expression by | The next step is to multiply the top and bottom of our new expression by | ||
- | <math>x+2</math>, | + | <math>x+2</math>, so as to obtain the final answer, |
- | so as to obtain the final answer, | + | |
- | + | ||
- | <math>\begin{align} | + | {{Displayed math||<math>\begin{align} |
- | + | \frac{1}{1+\dfrac{x+1}{x+2}}\cdot\frac{x+2}{x+2} | |
- | & | + | &= \frac{x+2}{\Bigl(1+\dfrac{x+1}{x+2}\Bigr)(x+2)}\\[8pt] |
- | + | &= \frac{x+2}{x+2+\dfrac{x+1}{x+2}(x+2)}\\[8pt] | |
- | + | &= \frac{x+2}{x+2+x+1}\\[8pt] | |
- | \end{align}</math> | + | &= \frac{x+2}{2x+3}\,\textrm{.} |
+ | \end{align}</math>}} |
Version vom 12:41, 23. Sep. 2008
When we come across large and complicated expressions, we have to work step by step; as a first goal, we can multiply the top and bottom of the fraction
by \displaystyle 1+x, so as to reduce it to an expression having one fraction sign
The next step is to multiply the top and bottom of our new expression by \displaystyle x+2, so as to obtain the final answer,