Lösung 1.3:5b

Aus Online Mathematik Brückenkurs 1

(Unterschied zwischen Versionen)
Wechseln zu: Navigation, Suche
K
Zeile 1: Zeile 1:
-
If we use
+
If we use <math>4 = 2\cdot 2 = 2^{2}</math>, the power rules give
-
<math>4=2\centerdot 2=2^{2}</math>, the power rules give
+
-
 
+
{{Displayed math||<math>4^{-\frac{1}{2}} = \bigl( 2^{2}\bigr)^{-\frac{1}{2}} = 2^{2\cdot (-\frac{1}{2})} = 2^{-1} = \frac{1}{2}\,</math>.}}
-
<math>4^{-\frac{1}{2}}=\left( 2^{2} \right)^{-\frac{1}{2}}=2^{2\centerdot \left( -\frac{1}{2} \right)}=2^{-1}=\frac{1}{2}</math>
+

Version vom 14:24, 22. Sep. 2008

If we use \displaystyle 4 = 2\cdot 2 = 2^{2}, the power rules give

Vorlage:Displayed math

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_1.3:5b“