Lösung 1.1:5b

Aus Online Mathematik Brückenkurs 1

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K (Lösning 1.1:5b moved to Solution 1.1:5b: Robot: moved page)
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We write the numbers in decimal form and then compare them. By using
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<center> [[Image:1_1_5b.gif]] </center>
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<math>{1}/{10}\;=0.1,\quad {1}/{5}\;=0.2</math>
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and
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<math>{1}/{3}\;=0.333...</math>, we have
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<math>\begin{align}
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& -\frac{1}{2}=-0.5 \\
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& \\
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& -\frac{1}{5}=-0.2 \\
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& \\
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& -\frac{3}{10}=-0.3 \\
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& \\
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& -\frac{1}{3}=-0.333... \\
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\end{align}</math>
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If we just remember that these are negative numbers, we can see directly that
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<math>\begin{align}
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& -\frac{1}{2}<-\frac{1}{3}<-\frac{3}{10}<-\frac{1}{5} \\
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& \\
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\end{align}</math>

Version vom 09:16, 22. Sep. 2008

We write the numbers in decimal form and then compare them. By using \displaystyle {1}/{10}\;=0.1,\quad {1}/{5}\;=0.2 and \displaystyle {1}/{3}\;=0.333..., we have


\displaystyle \begin{align} & -\frac{1}{2}=-0.5 \\ & \\ & -\frac{1}{5}=-0.2 \\ & \\ & -\frac{3}{10}=-0.3 \\ & \\ & -\frac{1}{3}=-0.333... \\ \end{align}

If we just remember that these are negative numbers, we can see directly that


\displaystyle \begin{align} & -\frac{1}{2}<-\frac{1}{3}<-\frac{3}{10}<-\frac{1}{5} \\ & \\ \end{align}

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_1.1:5b“