Lösung 2.2:1b
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
K (Lösning 2.2:1b moved to Solution 2.2:1b: Robot: moved page) |
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| - | + | To get | |
| - | < | + | <math>x</math> |
| - | {{ | + | by itself on the left-hand side, we subtract |
| + | <math>1</math> | ||
| + | from both sides | ||
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| + | |||
| + | <math>2x+1-1=13-1</math> | ||
| + | |||
| + | |||
| + | which gives | ||
| + | |||
| + | |||
| + | <math>2x=12</math> | ||
| + | |||
| + | Then divide both sides by 2, | ||
| + | |||
| + | |||
| + | <math>\frac{2x}{2}=\frac{12}{2}</math> | ||
| + | |||
| + | |||
| + | to get | ||
| + | <math>x</math>: | ||
| + | |||
| + | |||
| + | <math>x=6</math> | ||
Version vom 14:13, 16. Sep. 2008
To get \displaystyle x by itself on the left-hand side, we subtract \displaystyle 1 from both sides
\displaystyle 2x+1-1=13-1
which gives
\displaystyle 2x=12
Then divide both sides by 2,
\displaystyle \frac{2x}{2}=\frac{12}{2}
to get
\displaystyle x:
\displaystyle x=6
