Lösung 1.1:7a

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Multiplicerar vi talet 3,14 med 100 så flyttas decimalkommat två steg åt höger, dvs.
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If we multiply 3.14 by 100 the decimal point will move two places to the right, i.e.
::<math>100\cdot 3{,}14 = 314</math>
::<math>100\cdot 3{,}14 = 314</math>
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och delar vi båda led med 100 ser vi att
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and dividing both sides by 100 we see
::<math>3{,}14 = \frac{314}{100}\,\mbox{.}</math>
::<math>3{,}14 = \frac{314}{100}\,\mbox{.}</math>
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Detta visar att 3,14 kan skrivas som en kvot mellan två heltal och därmed att det är ett rationellt tal.
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This shows that 3.14 can be written as the quotient of two integers which means it is a rational number.
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Version vom 13:43, 14. Sep. 2008

If we multiply 3.14 by 100 the decimal point will move two places to the right, i.e.

\displaystyle 100\cdot 3{,}14 = 314

and dividing both sides by 100 we see

\displaystyle 3{,}14 = \frac{314}{100}\,\mbox{.}

This shows that 3.14 can be written as the quotient of two integers which means it is a rational number.

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_1.1:7a“