Lösung 1.2:1e
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
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- | {{ | + | The first step is to expand the fractions so that they have a common denominator, |
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+ | <math>\frac{8\centerdot 4\centerdot 3}{7\centerdot 4\centerdot 3}+\frac{3\centerdot 7\centerdot 3}{4\centerdot 7\centerdot 3}-\frac{4\centerdot 7\centerdot 4}{3\centerdot 7\centerdot 4}=\frac{96}{84}+\frac{63}{84}-\frac{112}{84}</math> | ||
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+ | After that, the expression can be calculated by adding and subtracting the numerators | ||
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+ | <math>\frac{96}{84}+\frac{63}{84}-\frac{112}{84}=\frac{96+63-112}{84}=\frac{47}{84}</math> |
Version vom 12:18, 11. Sep. 2008
The first step is to expand the fractions so that they have a common denominator,
\displaystyle \frac{8\centerdot 4\centerdot 3}{7\centerdot 4\centerdot 3}+\frac{3\centerdot 7\centerdot 3}{4\centerdot 7\centerdot 3}-\frac{4\centerdot 7\centerdot 4}{3\centerdot 7\centerdot 4}=\frac{96}{84}+\frac{63}{84}-\frac{112}{84}
After that, the expression can be calculated by adding and subtracting the numerators
\displaystyle \frac{96}{84}+\frac{63}{84}-\frac{112}{84}=\frac{96+63-112}{84}=\frac{47}{84}