Lösung 1.2:1e

Aus Online Mathematik Brückenkurs 1

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The first step is to expand the fractions so that they have a common denominator,
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<center> [[Image:1_2_1e.gif]] </center>
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<math>\frac{8\centerdot 4\centerdot 3}{7\centerdot 4\centerdot 3}+\frac{3\centerdot 7\centerdot 3}{4\centerdot 7\centerdot 3}-\frac{4\centerdot 7\centerdot 4}{3\centerdot 7\centerdot 4}=\frac{96}{84}+\frac{63}{84}-\frac{112}{84}</math>
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After that, the expression can be calculated by adding and subtracting the numerators
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<math>\frac{96}{84}+\frac{63}{84}-\frac{112}{84}=\frac{96+63-112}{84}=\frac{47}{84}</math>

Version vom 12:18, 11. Sep. 2008

The first step is to expand the fractions so that they have a common denominator,


\displaystyle \frac{8\centerdot 4\centerdot 3}{7\centerdot 4\centerdot 3}+\frac{3\centerdot 7\centerdot 3}{4\centerdot 7\centerdot 3}-\frac{4\centerdot 7\centerdot 4}{3\centerdot 7\centerdot 4}=\frac{96}{84}+\frac{63}{84}-\frac{112}{84}

After that, the expression can be calculated by adding and subtracting the numerators


\displaystyle \frac{96}{84}+\frac{63}{84}-\frac{112}{84}=\frac{96+63-112}{84}=\frac{47}{84}

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_1.2:1e“