Lösung 1.2:1b

Aus Online Mathematik Brückenkurs 1

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Subtraction works in the same way as addition. First, we multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator,
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<center> [[Image:1_2_1b.gif]] </center>
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<math>\frac{2\centerdot 5}{7\centerdot 5}-\frac{1\centerdot 7}{5\centerdot 7}=\frac{10}{35}-\frac{7}{35}</math>
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Then the numerators can be subtracted:
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<math>\frac{10}{35}-\frac{7}{35}=\frac{10-7}{35}=\frac{3}{35}</math>

Version vom 11:32, 11. Sep. 2008

Subtraction works in the same way as addition. First, we multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator,


\displaystyle \frac{2\centerdot 5}{7\centerdot 5}-\frac{1\centerdot 7}{5\centerdot 7}=\frac{10}{35}-\frac{7}{35}

Then the numerators can be subtracted:


\displaystyle \frac{10}{35}-\frac{7}{35}=\frac{10-7}{35}=\frac{3}{35}

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_1.2:1b“