Processing Math: Done
To print higher-resolution math symbols, click the
Hi-Res Fonts for Printing button on the jsMath control panel.
No jsMath TeX fonts found -- using image fonts instead.
These may be slow and might not print well.
Use the jsMath control panel to get additional information.
jsMath Control PanelHide this Message

jsMath

Lösung 2.1:2a

Aus Online Mathematik Brückenkurs 1

(Unterschied zwischen Versionen)
Wechseln zu: Navigation, Suche
K (Robot: Automated text replacement (-[[Bild: +[[Image:))
K (Lösning 2.1:2a moved to Solution 2.1:2a: Robot: moved page)

Version vom 08:33, 9. Sep. 2008

First, multiply the brackets together. In the first product, every term in the first bracket is multiplied by every term in the second bracket,

(x−4)(x−5)−3x(2x−3)=xx−x5−4x−4(−5)−(3x2x−3x3)=x2−5x−4x+20−(6x2−9x)=x2−5x−4x+20−6x2+9x

Then, gather together x2−x− and the constant terms and simplify

=(x2−6x2)+(−5x−4x+9x)+20=−5x2+0+20=−5x2+20

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_2.1:2a“