Antwort 4.4:5
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%" | <math>\left\{\eqalign{ x&=n\pi\cr x&=\displaystyle \frac{\pi}{4}+\displaystyle \frac{n\pi}{2} }\right.</math> |b) |width="50%" | <math...) |
K (Svar 4.4:5 moved to Answer 4.4:5: Robot: moved page) |
Version vom 14:58, 8. Sep. 2008
| a) | \displaystyle \left\{\eqalign{
x&=n\pi\cr x&=\displaystyle \frac{\pi}{4}+\displaystyle \frac{n\pi}{2} }\right. | b) | \displaystyle x=\displaystyle \frac{n\pi}{3} |
| c) | \displaystyle \left\{\eqalign{
x&=\displaystyle \frac{\pi}{20}+\displaystyle \frac{n\pi}{2}\cr x&=-\displaystyle \frac{\pi}{30}+\displaystyle \frac{n\pi}{3} }\right. |
