Antwort 4.4:3
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%" | <math>\left\{\eqalign{ x&=\displaystyle\frac{\pi}{6}+2n\pi\cr x&=\displaystyle\frac{11\pi}{6}+2n\pi }\right.</math> |b) |width="50%" |...) |
K (Svar 4.4:3 moved to Answer 4.4:3: Robot: moved page) |
Version vom 14:58, 8. Sep. 2008
| a) | \displaystyle \left\{\eqalign{
x&=\displaystyle\frac{\pi}{6}+2n\pi\cr x&=\displaystyle\frac{11\pi}{6}+2n\pi }\right. | b) | \displaystyle \left\{\eqalign{
x&=\displaystyle\frac{\pi}{5}+2n\pi\cr x&=\displaystyle\frac{4\pi}{5}+2n\pi }\right. |
| c) | \displaystyle \left\{\eqalign{
x&=25^\circ + n\cdot 360^\circ\cr x&=75^\circ + n\cdot 360^\circ }\right. | d) | \displaystyle \left\{\eqalign{
x&=5^\circ + n \cdot 120^\circ \cr x&= 55^\circ + n \cdot 120^\circ }\right. |
