Antwort 4.4:2
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
K (Svar 4.4:2 moved to Answer 4.4:2: Robot: moved page) |
Version vom 14:57, 8. Sep. 2008
| a) | \displaystyle \left\{\eqalign{
x&=\displaystyle\frac{\pi}{3}+2n\pi\cr x&=\displaystyle\frac{2\pi}{3}+2n\pi } \right. | b) | \displaystyle \left\{\eqalign{
x&=\displaystyle\frac{\pi}{3}+2n\pi\cr x&=\displaystyle\frac{5\pi}{3}+2n\pi } \right. | c) | \displaystyle x=n\pi |
| d) | \displaystyle \left\{\eqalign{
x&=\displaystyle\frac{\pi}{20}+\displaystyle\frac{2n\pi}{5}\cr x&=\displaystyle\frac{3\pi}{20}+\displaystyle\frac{2n\pi}{5} } \right. | e) | \displaystyle \left\{\eqalign{
x&=\displaystyle\frac{\pi}{30}+\displaystyle\frac{2n\pi}{5}\cr x&=\displaystyle\frac{\pi}{6}+\displaystyle\frac{2n\pi}{5}} \right. | f) | \displaystyle \left\{\eqalign{
x&=\displaystyle\frac{\pi}{4}+\displaystyle\frac{2n\pi}{3}\cr x&=\displaystyle\frac{5\pi}{12}+\displaystyle\frac{2n\pi}{3}} \right. |
