Antwort 3.4:2
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
(Translated into English) |
K (Svar 3.4:2 moved to Answer 3.4:2: Robot: moved page) |
Version vom 14:48, 8. Sep. 2008
| a) | \displaystyle \left\{ \eqalign{ x_1&=\sqrt2 \cr x_2&=-\sqrt2 } \right. | b) | \displaystyle x=\ln \left(\displaystyle\frac{\sqrt17}{2}-\frac{1}{2}\right) | c) | No solution |
