Antwort 4.2:1
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
			  			                                                      
		          
			 (Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%" | <math>x=13\cdot\tan {27 ^\circ} \approx 6{,}62</math> |b) |width="50%"  | <math>x=25\cdot\cos {32 ^\circ} \approx 21{,}2</math> |- |c) ...)  | 
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{| width="100%" cellspacing="10px"  | {| width="100%" cellspacing="10px"  | ||
|a)  | |a)  | ||
| - | |width="50%" | <math>x=13\cdot\tan {27 ^\circ} \approx 6{  | + | |width="50%" | <math>x=13\cdot\tan {27 ^\circ} \approx 6\textrm{.}62</math>  | 
|b)  | |b)  | ||
| - | |width="50%"  | <math>x=25\cdot\cos {32 ^\circ} \approx 21{  | + | |width="50%"  | <math>x=25\cdot\cos {32 ^\circ} \approx 21\textrm{.}2</math>  | 
|-  | |-  | ||
|c)  | |c)  | ||
| - | |width="50%" | <math>x=\displaystyle\frac{14}{\tan {40 ^\circ}} \approx 16{  | + | |width="50%" | <math>x=\displaystyle\frac{14}{\tan {40 ^\circ}} \approx 16\textrm{.}7</math>  | 
|d)  | |d)  | ||
| - | |width="50%" | <math>x=\displaystyle\frac{16}{\cos {20 ^\circ}} \approx 17{  | + | |width="50%" | <math>x=\displaystyle\frac{16}{\cos {20 ^\circ}} \approx 17\textrm{.}0</math>  | 
|-  | |-  | ||
|e)  | |e)  | ||
| - | |width="50%" | <math>x=\displaystyle\frac{11}{\sin {35 ^\circ}} \approx 19{  | + | |width="50%" | <math>x=\displaystyle\frac{11}{\sin {35 ^\circ}} \approx 19\textrm{.}2</math>  | 
|f)  | |f)  | ||
| - | |width="50%" | <math>x=\displaystyle\frac{19}{\tan {50 ^\circ}} \approx 15{  | + | |width="50%" | <math>x=\displaystyle\frac{19}{\tan {50 ^\circ}} \approx 15\textrm{.}9</math>  | 
|}  | |}  | ||
Version vom 10:56, 8. Sep. 2008
| a) | \displaystyle x=13\cdot\tan {27 ^\circ} \approx 6\textrm{.}62 | b) | \displaystyle x=25\cdot\cos {32 ^\circ} \approx 21\textrm{.}2 | 
| c) | \displaystyle x=\displaystyle\frac{14}{\tan {40 ^\circ}} \approx 16\textrm{.}7 | d) | \displaystyle x=\displaystyle\frac{16}{\cos {20 ^\circ}} \approx 17\textrm{.}0 | 
| e) | \displaystyle x=\displaystyle\frac{11}{\sin {35 ^\circ}} \approx 19\textrm{.}2 | f) | \displaystyle x=\displaystyle\frac{19}{\tan {50 ^\circ}} \approx 15\textrm{.}9 | 
