Lösung 2.1:3d
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
(Ny sida: {{NAVCONTENT_START}} <center> Bild:2_1_3d.gif </center> {{NAVCONTENT_STOP}}) |
|||
| Zeile 1: | Zeile 1: | ||
{{NAVCONTENT_START}} | {{NAVCONTENT_START}} | ||
| - | <center> [[Bild:2_1_3d.gif]] </center> | + | By writing the expression as <math> x^2 -2\cdot 5x +5^5 </math>, applying the squaring rule <math> x^2-2ax +a^2=(x-a)^2 </math> then gives |
| + | |||
| + | <math> \qquad | ||
| + | x^2 -10x +5^5 =x^2 -2\cdot 5x +5^5 =(x-5)^2 | ||
| + | </math> | ||
| + | <!--<center> [[Bild:2_1_3d.gif]] </center>--> | ||
{{NAVCONTENT_STOP}} | {{NAVCONTENT_STOP}} | ||
Version vom 13:12, 13. Aug. 2008
By writing the expression as \displaystyle x^2 -2\cdot 5x +5^5 , applying the squaring rule \displaystyle x^2-2ax +a^2=(x-a)^2 then gives
\displaystyle \qquad x^2 -10x +5^5 =x^2 -2\cdot 5x +5^5 =(x-5)^2
