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Lösung 2.1:1a

Aus Online Mathematik Brückenkurs 1

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Using the distributivity rule, we can multiply the factor <math> 3x </math> into the bracket <math> (x-1) </math>. Each term in <math> (x-1)</math> is then to be multiplied by <math> 3x. </math>
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Using the distributivity rule, we can multiply the factor <math> 3x </math> into the bracket <math> (x-1) </math>. Each term in <math> (x-1)</math> is then to be multiplied by <math> 3x, </math>
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:<math> 3x(x-1)=3x\cdot x - 3x \cdot 1 = 3x^2-3x </math>
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:<math> 3x(x-1)=3x\cdot x - 3x \cdot 1 = 3x^2-3x. </math>

Version vom 08:15, 13. Aug. 2008


Using the distributivity rule, we can multiply the factor 3x into the bracket (x−1). Each term in (x−1) is then to be multiplied by 3x

3x(x−1)=3xx−3x1=3x2−3x
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_2.1:1a“