Lösung 3.3:3g - Versionsgeschichte

Markus.bez um 10:57, 12. Jun. 2009

Markus.bez — Fri, 12 Jun 2009 10:57:12 GMT

← Nächstältere Version		Version vom 10:57, 12. Jun. 2009
Zeile 1:		Zeile 1:
-	Wir verwenden das Logarithmengesetz <math>\lg a-\lg b = \lg\frac{a}{b}\,</math>,	+	Wir verwenden das Logarithmengesetz <math>\lg a-\lg b = \lg\frac{a}{b}\,</math>:

	{{Abgesetzte Formel\|\|<math>\log_3 12 - \log_3 4 = \log_3\frac{12}{4} = \log _3 3 = 1\,\textrm{.}</math>}}		{{Abgesetzte Formel\|\|<math>\log_3 12 - \log_3 4 = \log_3\frac{12}{4} = \log _3 3 = 1\,\textrm{.}</math>}}

-	Alternativ schreibt man <math>12 = 3\cdot 4</math> und verwendet das Logarithmengesetz <math>\lg (ab) = \lg a + \lg b\,</math>,	+	Alternativ schreibt man <math>12 = 3\cdot 4</math> und verwendet das Logarithmengesetz <math>\lg (ab) = \lg a + \lg b\,</math>:

	{{Abgesetzte Formel\|\|<math>\begin{align}		{{Abgesetzte Formel\|\|<math>\begin{align}

Martin — Thu, 26 Mar 2009 20:27:26 GMT

← Nächstältere Version		Version vom 20:27, 26. Mär. 2009
Zeile 1:		Zeile 1:
-	~~Using the logarithm law,~~ <math>\lg a-\lg b = \lg\frac{a}{b}\,</math>, ~~the expression can be calculated as~~	+	Wir verwenden das Logarithmengesetz <math>\lg a-\lg b = \lg\frac{a}{b}\,</math>,

	{{Abgesetzte Formel\|\|<math>\log_3 12 - \log_3 4 = \log_3\frac{12}{4} = \log _3 3 = 1\,\textrm{.}</math>}}		{{Abgesetzte Formel\|\|<math>\log_3 12 - \log_3 4 = \log_3\frac{12}{4} = \log _3 3 = 1\,\textrm{.}</math>}}

-	~~Another way is to write~~ <math>12 = 3\cdot 4</math> ~~and use the logarithm law,~~	+	Alternativ schreibt man <math>12 = 3\cdot 4</math> und verwendet das Logarithmengesetz <math>\lg (ab) = \lg a + \lg b\,</math>,
-	<math>\lg (ab) = \lg a + \lg b\,</math>,	+

	{{Abgesetzte Formel\|\|<math>\begin{align}		{{Abgesetzte Formel\|\|<math>\begin{align}

Tekbot — Wed, 22 Oct 2008 14:35:44 GMT

hat „Solution 3.3:3g“ nach „Lösung 3.3:3g“ verschoben: Robot: moved page

← Nächstältere Version

Version vom 14:35, 22. Okt. 2008

Tekbot — Wed, 22 Oct 2008 08:43:28 GMT

Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel)

← Nächstältere Version		Version vom 08:43, 22. Okt. 2008
Zeile 1:		Zeile 1:
	Using the logarithm law, <math>\lg a-\lg b = \lg\frac{a}{b}\,</math>, the expression can be calculated as		Using the logarithm law, <math>\lg a-\lg b = \lg\frac{a}{b}\,</math>, the expression can be calculated as

-	{{~~Displayed math~~\|\|<math>\log_3 12 - \log_3 4 = \log_3\frac{12}{4} = \log _3 3 = 1\,\textrm{.}</math>}}	+	{{Abgesetzte Formel\|\|<math>\log_3 12 - \log_3 4 = \log_3\frac{12}{4} = \log _3 3 = 1\,\textrm{.}</math>}}

	Another way is to write <math>12 = 3\cdot 4</math> and use the logarithm law,		Another way is to write <math>12 = 3\cdot 4</math> and use the logarithm law,
	<math>\lg (ab) = \lg a + \lg b\,</math>,		<math>\lg (ab) = \lg a + \lg b\,</math>,

-	{{~~Displayed math~~\|\|<math>\begin{align}	+	{{Abgesetzte Formel\|\|<math>\begin{align}
	\log _{3}12 - \log _{3}4		\log _{3}12 - \log _{3}4
	&= \log_{3}(3\cdot 4) - \log_{3} 4\\[5pt]		&= \log_{3}(3\cdot 4) - \log_{3} 4\\[5pt]

Tek — Thu, 02 Oct 2008 07:00:44 GMT

← Nächstältere Version		Version vom 07:00, 2. Okt. 2008
Zeile 1:		Zeile 1:
-	Using the logarithm law,	+	Using the logarithm law, <math>\lg a-\lg b = \lg\frac{a}{b}\,</math>, the expression can be calculated as
-	<math>\lg a-\lg b=\lg ~~\left(~~ \frac{a}{b} \~~right)~~</math>, the expression can be calculated as	+

		+	{{Displayed math\|\|<math>\log_3 12 - \log_3 4 = \log_3\frac{12}{4} = \log _3 3 = 1\,\textrm{.}</math>}}

-	<math>~~\log _{3}~~12~~-\log _{3}4~~=~~\log _{~~3}\~~frac{12}{~~4}=\~~log _{3}3~~=1</math>	+	Another way is to write <math>12 = 3\cdot 4</math> and use the logarithm law,
		+	<math>\lg (ab) = \lg a + \lg b\,</math>,

-		+	{{Displayed math\|\|<math>\begin{align}
-	~~Another way is to write~~	+	\log _{3}12 - \log _{3}4
-	~~<math>\text~~{~~12}=\text~~{~~3}\centerdot \text{4 }</~~math>	+	&= \log_{3}(3\cdot 4) - \log_{3} 4\\[5pt]
-	~~and use the logarithm law,~~	+	&= \log_{3}3 + \log _{3}4 - \log _{3}4\\[5pt]
-	~~<math>\lg \left( ab \right)=\lg a+\lg b</math>,~~	+	&= \log _{3}3\\[5pt]
-		+	&= 1\,\textrm{.}
-		+	\end{align}</math>}}
-	<math>\begin{align}	+
-	& \log _{3}12-\log _{3}4=\~~log _~~{3}~~\left~~( 3\~~centerdot~~ 4 ~~\right~~)-\~~log _~~{3}4 \\	+
-	& =\~~log _~~{3}3+\log _{3}4-\log _{3}4=\log _{3}3=1 \\	+
-	\end{align}</math>	+

Ian — Thu, 25 Sep 2008 14:33:16 GMT

← Nächstältere Version		Version vom 14:33, 25. Sep. 2008
Zeile 1:		Zeile 1:
-	{{~~NAVCONTENT_START~~}}	+	Using the logarithm law,
-	<~~center~~> ~~[[Image:3_3_3g.gif]]~~ </~~center~~>	+	<math>\lg a-\lg b=\lg \left( \frac{a}{b} \right)</math>, the expression can be calculated as
-	{{~~NAVCONTENT_STOP~~}}	+
		+
		+	<math>\log _{3}12-\log _{3}4=\log _{3}\frac{12}{4}=\log _{3}3=1</math>
		+
		+
		+	Another way is to write
		+	<math>\text{12}=\text{3}\centerdot \text{4 }</math>
		+	and use the logarithm law,
		+	<math>\lg \left( ab \right)=\lg a+\lg b</math>,
		+
		+
		+	<math>\begin{align}
		+	& \log _{3}12-\log _{3}4=\log _{3}\left( 3\centerdot 4 \right)-\log _{3}4 \\
		+	& =\log _{3}3+\log _{3}4-\log _{3}4=\log _{3}3=1 \\
		+	\end{align}</math>

Tekbot — Tue, 09 Sep 2008 09:25:23 GMT

← Nächstältere Version

Version vom 09:25, 9. Sep. 2008

Tekbot — Thu, 21 Aug 2008 06:59:49 GMT

Robot: Automated text replacement (-[[Bild: +[[Image:)

Oskar — Wed, 02 Apr 2008 09:47:21 GMT

Ny sida: {{NAVCONTENT_START}} <center> Bild:3_3_3g.gif </center> {{NAVCONTENT_STOP}}

Neue Seite

{{NAVCONTENT_START}}
<center> [[Bild:3_3_3g.gif]] </center>
{{NAVCONTENT_STOP}}