Lösung 2.3:9a - Versionsgeschichte

Tek: Replaced figure with metapost figure

Tek — Wed, 19 Aug 2009 13:07:00 GMT

Replaced figure with metapost figure

← Nächstältere Version		Version vom 13:07, 19. Aug. 2009
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-	~~[[Image~~:~~2_3_9_a~~.~~gif\|~~center]]	+	<center>{{:2.3.9a - Solution - The parabola y = x² - 1 and points (-1,0) and (1,0)}}</center>

Markus.bez — Tue, 09 Jun 2009 14:02:22 GMT

← Nächstältere Version		Version vom 14:02, 9. Jun. 2009
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-	Jeder Punkt auf der ''x''-Achse, hat ~~den~~ ''y''~~.Koordinaten~~ 0, und daher müssen die Schnittpunkte folgende Gleichung erfüllen	+	Jeder Punkt der Parabel, der ebenfalls auf der ''x''-Achse liegt, hat die ''y''-Koordinate 0, und daher müssen die Schnittpunkte folgende Gleichung erfüllen:

	{{Abgesetzte Formel\|\|<math>0=x^{2}-1\,\textrm{.}</math>}}		{{Abgesetzte Formel\|\|<math>0=x^{2}-1\,\textrm{.}</math>}}

Martin — Mon, 16 Mar 2009 19:54:00 GMT

← Nächstältere Version		Version vom 19:54, 16. Mär. 2009
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-	~~A point lies on the~~ ''x''-~~axis if it has~~ ''y''~~-coordinate~~ 0 ~~and we therefore look for all the points on the curve <math>y=x^{2}-1</math> where <math>y=0</math>~~, ~~i.e. all points which satisfy the equation~~	+	Jeder Punkt auf der ''x''-Achse, hat den ''y''.Koordinaten 0, und daher müssen die Schnittpunkte folgende Gleichung erfüllen

	{{Abgesetzte Formel\|\|<math>0=x^{2}-1\,\textrm{.}</math>}}		{{Abgesetzte Formel\|\|<math>0=x^{2}-1\,\textrm{.}</math>}}

-	~~This equation has solutions~~ <math>x=\pm 1</math>, ~~which means that the points of intersection are~~ <math>(-1,0)</math> ~~and~~ <math>(1,0)</math>.	+	Diese Gleichung hat die Lösungen <math>x=\pm 1</math>, und also sind die Schnittpunkte <math>(-1,0)</math> und <math>(1,0)</math>.


	[[Image:2_3_9_a.gif\|center]]		[[Image:2_3_9_a.gif\|center]]

Tekbot — Wed, 22 Oct 2008 14:15:25 GMT

hat „Solution 2.3:9a“ nach „Lösung 2.3:9a“ verschoben: Robot: moved page

← Nächstältere Version

Version vom 14:15, 22. Okt. 2008

Tekbot — Wed, 22 Oct 2008 08:34:58 GMT

Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel)

← Nächstältere Version		Version vom 08:34, 22. Okt. 2008
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	A point lies on the ''x''-axis if it has ''y''-coordinate 0 and we therefore look for all the points on the curve <math>y=x^{2}-1</math> where <math>y=0</math>, i.e. all points which satisfy the equation		A point lies on the ''x''-axis if it has ''y''-coordinate 0 and we therefore look for all the points on the curve <math>y=x^{2}-1</math> where <math>y=0</math>, i.e. all points which satisfy the equation

-	{{~~Displayed math~~\|\|<math>0=x^{2}-1\,\textrm{.}</math>}}	+	{{Abgesetzte Formel\|\|<math>0=x^{2}-1\,\textrm{.}</math>}}

	This equation has solutions <math>x=\pm 1</math>, which means that the points of intersection are <math>(-1,0)</math> and <math>(1,0)</math>.		This equation has solutions <math>x=\pm 1</math>, which means that the points of intersection are <math>(-1,0)</math> and <math>(1,0)</math>.

Tek — Mon, 29 Sep 2008 13:14:29 GMT

← Nächstältere Version		Version vom 13:14, 29. Sep. 2008
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-	A point lies on the	+	A point lies on the ''x''-axis if it has ''y''-coordinate 0 and we therefore look for all the points on the curve <math>y=x^{2}-1</math> where <math>y=0</math>, i.e. all points which satisfy the equation
-	~~<math>~~x~~</math>~~	+
-	-axis if it has	+
-	~~<math>~~y~~</math>~~	+
-	-coordinate	+
-	~~<math>~~0~~</math>~~	+
-	and we therefore look for all the points on the curve	+
-	<math>y=x^~~{\text~~{2}}-~~\text{~~1}</math>	+
-	where	+
-	<math>y=0</math>, i.e. all points which satisfy the equation	+

		+	{{Displayed math\|\|<math>0=x^{2}-1\,\textrm{.}</math>}}

-	~~<math>0=x^{\text{2}}-\text{1}</math>~~	+	This equation has solutions <math>x=\pm 1</math>, which means that the points of intersection are <math>(-1,0)</math> and <math>(1,0)</math>.
-		+
-		+
-	This equation has solutions	+
-	<math>x=\pm ~~\text{~~1}</math>, which means that the points of intersection are	+
-	<math>~~\left~~( -1 ~~\right.~~,~~\left.~~ 0 ~~\right~~)</math>	+
-	and	+
-	<math>~~\left~~( 1 ~~\right.~~,~~\left.~~ 0 ~~\right~~)</math>.	+


	[[Image:2_3_9_a.gif\|center]]		[[Image:2_3_9_a.gif\|center]]

Ian — Sun, 21 Sep 2008 11:43:00 GMT

← Nächstältere Version		Version vom 11:43, 21. Sep. 2008
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-	{{~~NAVCONTENT_START~~}}	+	A point lies on the
-	<~~center~~> ~~[[Image:2_3_9a.gif]]~~ </~~center~~>	+	<math>x</math>
-	{{~~NAVCONTENT_STOP~~}}	+	-axis if it has
		+	<math>y</math>
		+	-coordinate
		+	<math>0</math>
		+	and we therefore look for all the points on the curve
		+	<math>y=x^{\text{2}}-\text{1}</math>
		+	where
		+	<math>y=0</math>, i.e. all points which satisfy the equation
		+
		+
		+	<math>0=x^{\text{2}}-\text{1}</math>
		+
		+
		+	This equation has solutions
		+	<math>x=\pm \text{1}</math>, which means that the points of intersection are
		+	<math>\left( -1 \right.,\left. 0 \right)</math>
		+	and
		+	<math>\left( 1 \right.,\left. 0 \right)</math>.
		+
		+
	[[Image:2_3_9_a.gif\|center]]		[[Image:2_3_9_a.gif\|center]]

Tekbot — Tue, 09 Sep 2008 09:05:03 GMT

← Nächstältere Version

Version vom 09:05, 9. Sep. 2008

Tekbot — Thu, 21 Aug 2008 06:49:39 GMT

Robot: Automated text replacement (-[[Bild: +[[Image:)

Madde — Fri, 15 Aug 2008 11:43:16 GMT