Lösung 2.2:6d - Versionsgeschichte

Tek: Replaced figure with metapost figure

Tek — Tue, 18 Aug 2009 12:52:37 GMT

Replaced figure with metapost figure

← Nächstältere Version		Version vom 12:52, 18. Aug. 2009
Zeile 10:		Zeile 10:


-	<center>~~[[Image~~:~~2_2_6_d_de~~.~~gif\|center]]~~</center>	+	<center>{{:2.2.6d - Solution - The lines x + y + 1 = 0 and x = 12 through the point (12,-13)}}</center>

Bayerer — Thu, 30 Jul 2009 15:04:55 GMT

← Nächstältere Version		Version vom 15:04, 30. Jul. 2009
Zeile 10:		Zeile 10:


-	<center>[[Image:~~2_2_6_d~~.gif\|center]]</center>	+	<center>[[Image:2_2_6_d_de.gif\|center]]</center>

Markus.bez — Tue, 09 Jun 2009 09:52:36 GMT

← Nächstältere Version		Version vom 09:52, 9. Jun. 2009
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-	Der Schnittpunkt muss beide Gleichungen der Geraden erfüllen	+	Der Schnittpunkt muss beide Gleichungen der Geraden erfüllen, also

-	{{Abgesetzte Formel\|\|<math>x+y+1=0\qquad\text{~~and~~}\qquad x=12\,\textrm{.}</math>}}	+	{{Abgesetzte Formel\|\|<math>x+y+1=0\qquad\text{und}\qquad x=12\,\textrm{.}</math>}}

	Wir substituieren <math>x=12</math> in der ersten Gleichung und erhalten		Wir substituieren <math>x=12</math> in der ersten Gleichung und erhalten

Markus.bez — Tue, 09 Jun 2009 09:51:08 GMT

← Nächstältere Version		Version vom 09:51, 9. Jun. 2009
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	{{Abgesetzte Formel\|\|<math>x+y+1=0\qquad\text{and}\qquad x=12\,\textrm{.}</math>}}		{{Abgesetzte Formel\|\|<math>x+y+1=0\qquad\text{and}\qquad x=12\,\textrm{.}</math>}}

-	Wir substituieren <math>x=12</math> in der ersten Gleichung, und erhalten	+	Wir substituieren <math>x=12</math> in der ersten Gleichung und erhalten

	{{Abgesetzte Formel\|\|<math>12+y+1=0\quad\Leftrightarrow\quad y=-13\,\textrm{,}</math>}}		{{Abgesetzte Formel\|\|<math>12+y+1=0\quad\Leftrightarrow\quad y=-13\,\textrm{,}</math>}}

Martin — Fri, 13 Mar 2009 11:41:35 GMT

← Nächstältere Version		Version vom 11:41, 13. Mär. 2009
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-	~~At the point where the lines cut each other, we have a point that lies on both lines and which must therefore satisfy the equations of both lines,~~	+	Der Schnittpunkt muss beide Gleichungen der Geraden erfüllen

	{{Abgesetzte Formel\|\|<math>x+y+1=0\qquad\text{and}\qquad x=12\,\textrm{.}</math>}}		{{Abgesetzte Formel\|\|<math>x+y+1=0\qquad\text{and}\qquad x=12\,\textrm{.}</math>}}

-	~~We obtain the solution to this system of equations by substituting~~ <math>x=12</math>	+	Wir substituieren <math>x=12</math> in der ersten Gleichung, und erhalten
-	~~into the first equation~~	+

	{{Abgesetzte Formel\|\|<math>12+y+1=0\quad\Leftrightarrow\quad y=-13\,\textrm{,}</math>}}		{{Abgesetzte Formel\|\|<math>12+y+1=0\quad\Leftrightarrow\quad y=-13\,\textrm{,}</math>}}

-	~~which gives us the point of intersection as~~ (12,-13).	+	Also ist der Schnittpunkt (12,-13).


	<center>[[Image:2_2_6_d.gif\|center]]</center>		<center>[[Image:2_2_6_d.gif\|center]]</center>

Tekbot — Wed, 22 Oct 2008 14:00:05 GMT

hat „Solution 2.2:6d“ nach „Lösung 2.2:6d“ verschoben: Robot: moved page

← Nächstältere Version

Version vom 14:00, 22. Okt. 2008

Tekbot — Wed, 22 Oct 2008 08:29:48 GMT

Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel)

← Nächstältere Version		Version vom 08:29, 22. Okt. 2008
Zeile 1:		Zeile 1:
	At the point where the lines cut each other, we have a point that lies on both lines and which must therefore satisfy the equations of both lines,		At the point where the lines cut each other, we have a point that lies on both lines and which must therefore satisfy the equations of both lines,

-	{{~~Displayed math~~\|\|<math>x+y+1=0\qquad\text{and}\qquad x=12\,\textrm{.}</math>}}	+	{{Abgesetzte Formel\|\|<math>x+y+1=0\qquad\text{and}\qquad x=12\,\textrm{.}</math>}}

	We obtain the solution to this system of equations by substituting <math>x=12</math>		We obtain the solution to this system of equations by substituting <math>x=12</math>
	into the first equation		into the first equation

-	{{~~Displayed math~~\|\|<math>12+y+1=0\quad\Leftrightarrow\quad y=-13\,\textrm{,}</math>}}	+	{{Abgesetzte Formel\|\|<math>12+y+1=0\quad\Leftrightarrow\quad y=-13\,\textrm{,}</math>}}

	which gives us the point of intersection as (12,-13).		which gives us the point of intersection as (12,-13).

Tek — Wed, 24 Sep 2008 13:14:31 GMT

← Nächstältere Version		Version vom 13:14, 24. Sep. 2008
Zeile 1:		Zeile 1:
-	At the point where the lines cut each other, we have a point that lies on both lines and which must therefore satisfy the equations of both lines:	+	At the point where the lines cut each other, we have a point that lies on both lines and which must therefore satisfy the equations of both lines,

		+	{{Displayed math\|\|<math>x+y+1=0\qquad\text{and}\qquad x=12\,\textrm{.}</math>}}

-	~~<math>x+y+1=0</math>~~	+	We obtain the solution to this system of equations by substituting <math>x=12</math>
-	~~and~~	+
-	~~<math>x=12</math>.~~	+
-		+
-	We obtain the solution to this system of equations by substituting	+
-	<math>x=12</math>	+
	into the first equation		into the first equation

		+	{{Displayed math\|\|<math>12+y+1=0\quad\Leftrightarrow\quad y=-13\,\textrm{,}</math>}}

-	~~<math>12+y+1=0\ \Leftrightarrow \ y=-13</math>~~	+	which gives us the point of intersection as (12,-13).
-		+
-	which gives us the point of intersection as	+
-	~~<math>\left~~( 12 ~~\right.~~,~~\left.~~ -13 ~~\right~~)~~</math>~~.	+
-		+

-	{{NAVCONTENT_START}}
-	[[Image:2_2_6_d.gif\|center]]

-	~~{{NAVCONTENT_STOP}}~~	+	<center>[[Image:2_2_6_d.gif\|center]]</center>

Ian — Thu, 18 Sep 2008 11:39:49 GMT

← Nächstältere Version		Version vom 11:39, 18. Sep. 2008
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		+	At the point where the lines cut each other, we have a point that lies on both lines and which must therefore satisfy the equations of both lines:
		+
		+
		+	<math>x+y+1=0</math>
		+	and
		+	<math>x=12</math>.
		+
		+	We obtain the solution to this system of equations by substituting
		+	<math>x=12</math>
		+	into the first equation
		+
		+
		+	<math>12+y+1=0\ \Leftrightarrow \ y=-13</math>
		+
		+	which gives us the point of intersection as
		+	<math>\left( 12 \right.,\left. -13 \right)</math>.
		+
		+
	{{NAVCONTENT_START}}		{{NAVCONTENT_START}}
	[[Image:2_2_6_d.gif\|center]]		[[Image:2_2_6_d.gif\|center]]
-	~~<center> [[Image:2_2_6d.gif]] </center>~~	+
	{{NAVCONTENT_STOP}}		{{NAVCONTENT_STOP}}

Tekbot — Tue, 09 Sep 2008 08:49:43 GMT

← Nächstältere Version

Version vom 08:49, 9. Sep. 2008