Lösung 2.2:6b - Versionsgeschichte

Tek: Replaced figure with metapost figure

Tek — Tue, 18 Aug 2009 12:34:56 GMT

Replaced figure with metapost figure

← Nächstältere Version		Version vom 12:34, 18. Aug. 2009
Zeile 6:		Zeile 6:


-	<center>~~[[Image~~:~~2_2_6_b~~.~~gif]]~~</center>	+	<center>{{:2.2.6b - Solution - The line y = -x + 5 through the point (0,5)}}</center>

Markus.bez — Tue, 09 Jun 2009 09:50:22 GMT

← Nächstältere Version		Version vom 09:50, 9. Jun. 2009
Zeile 1:		Zeile 1:
	Nachdem der Schnittpunkt auf beiden Geraden liegt, muss er die Gleichung beider Geraden erfüllen		Nachdem der Schnittpunkt auf beiden Geraden liegt, muss er die Gleichung beider Geraden erfüllen

-	{{Abgesetzte Formel\|\|<math>y=-x+5\qquad\text{~~and~~}\qquad x=0\,,</math>}}	+	{{Abgesetzte Formel\|\|<math>y=-x+5\qquad\text{und}\qquad x=0\,,</math>}}

-	wo <math>x=0</math> die Gleichung der ''y''-Achse ist. Dies ~~substituiert~~ in ~~der ersten~~ Gleichung, ergibt <math>y=-0+5=5</math>. Also ist der Schnittpunkt (0,5).	+	wo <math>x=0</math> die Gleichung der ''y''-Achse ist. Dies eingesetzt in die erste Gleichung ergibt <math>y=-0+5=5</math>. Also ist der Schnittpunkt (0,5).


	<center>[[Image:2_2_6_b.gif]]</center>		<center>[[Image:2_2_6_b.gif]]</center>

Martin — Fri, 13 Mar 2009 11:36:55 GMT

← Nächstältere Version		Version vom 11:36, 13. Mär. 2009
Zeile 1:		Zeile 1:
-	~~Because the point of intersection lies on both lines~~, ~~it must satisfy the equations of both lines~~	+	Nachdem der Schnittpunkt auf beiden Geraden liegt, muss er die Gleichung beider Geraden erfüllen

	{{Abgesetzte Formel\|\|<math>y=-x+5\qquad\text{and}\qquad x=0\,,</math>}}		{{Abgesetzte Formel\|\|<math>y=-x+5\qquad\text{and}\qquad x=0\,,</math>}}

-	~~where~~ <math>x=0</math> ~~is the equation of the~~ ''y''-~~axis~~. ~~Substituting the second equation~~, ~~<math>x=0</math>, into the first equation gives~~ <math>y=-0+5=5</math>. ~~This means that the point of intersection is~~ (0,5).	+	wo <math>x=0</math> die Gleichung der ''y''-Achse ist. Dies substituiert in der ersten Gleichung, ergibt <math>y=-0+5=5</math>. Also ist der Schnittpunkt (0,5).


	<center>[[Image:2_2_6_b.gif]]</center>		<center>[[Image:2_2_6_b.gif]]</center>

Tekbot — Wed, 22 Oct 2008 13:59:25 GMT

hat „Solution 2.2:6b“ nach „Lösung 2.2:6b“ verschoben: Robot: moved page

← Nächstältere Version

Version vom 13:59, 22. Okt. 2008

Tekbot — Wed, 22 Oct 2008 08:29:28 GMT

Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel)

← Nächstältere Version		Version vom 08:29, 22. Okt. 2008
Zeile 1:		Zeile 1:
	Because the point of intersection lies on both lines, it must satisfy the equations of both lines		Because the point of intersection lies on both lines, it must satisfy the equations of both lines

-	{{~~Displayed math~~\|\|<math>y=-x+5\qquad\text{and}\qquad x=0\,,</math>}}	+	{{Abgesetzte Formel\|\|<math>y=-x+5\qquad\text{and}\qquad x=0\,,</math>}}

	where <math>x=0</math> is the equation of the ''y''-axis. Substituting the second equation, <math>x=0</math>, into the first equation gives <math>y=-0+5=5</math>. This means that the point of intersection is (0,5).		where <math>x=0</math> is the equation of the ''y''-axis. Substituting the second equation, <math>x=0</math>, into the first equation gives <math>y=-0+5=5</math>. This means that the point of intersection is (0,5).

Tek — Wed, 24 Sep 2008 13:04:42 GMT

← Nächstältere Version		Version vom 13:04, 24. Sep. 2008
Zeile 1:		Zeile 1:
	Because the point of intersection lies on both lines, it must satisfy the equations of both lines		Because the point of intersection lies on both lines, it must satisfy the equations of both lines

		+	{{Displayed math\|\|<math>y=-x+5\qquad\text{and}\qquad x=0\,,</math>}}

-	<math>y=-x+5</math>	+	where <math>x=0</math> is the equation of the ''y''-axis. Substituting the second equation, <math>x=0</math>, into the first equation gives <math>y=-0+5=5</math>. This means that the point of intersection is (0,5).
-	~~and~~	+
-	<math>x=0</math>,	+

-	where
-	<math>x=0</math>
-	is the equation of the
-	<math>y</math>
-	-axis. Substituting the other equation,
-	<math>x=0</math>, into the first equation gives
-	<math>y=-0+5=5</math>. This means that the point of intersection is
-	<math>\left( 0 \right.,\left. 5 \right)</math>.

-		+	<center>[[Image:2_2_6_b.gif]]</center>
-	~~{{NAVCONTENT_START}}~~	+
-	[[Image:2_2_6_b.gif]]	+
-		+
-	~~{{NAVCONTENT_STOP}}~~	+

Ian — Thu, 18 Sep 2008 10:24:24 GMT

← Nächstältere Version		Version vom 10:24, 18. Sep. 2008
Zeile 1:		Zeile 1:
		+	Because the point of intersection lies on both lines, it must satisfy the equations of both lines
		+
		+
		+	<math>y=-x+5</math>
		+	and
		+	<math>x=0</math>,
		+
		+	where
		+	<math>x=0</math>
		+	is the equation of the
		+	<math>y</math>
		+	-axis. Substituting the other equation,
		+	<math>x=0</math>, into the first equation gives
		+	<math>y=-0+5=5</math>. This means that the point of intersection is
		+	<math>\left( 0 \right.,\left. 5 \right)</math>.
		+
		+
	{{NAVCONTENT_START}}		{{NAVCONTENT_START}}
	[[Image:2_2_6_b.gif]]		[[Image:2_2_6_b.gif]]
-	~~<center> [[Image:2_2_6b.gif]] </center>~~	+
	{{NAVCONTENT_STOP}}		{{NAVCONTENT_STOP}}

Tekbot — Tue, 09 Sep 2008 08:49:03 GMT

← Nächstältere Version

Version vom 08:49, 9. Sep. 2008

Tekbot — Thu, 21 Aug 2008 06:41:39 GMT

Robot: Automated text replacement (-[[Bild: +[[Image:)

Martin — Fri, 15 Aug 2008 11:15:55 GMT