Lösung 2.2:5b - Versionsgeschichte

Tek: Replaced figure with metapost figure

Tek — Tue, 18 Aug 2009 11:16:17 GMT

Replaced figure with metapost figure

← Nächstältere Version		Version vom 11:16, 18. Aug. 2009
Zeile 12:		Zeile 12:


-	~~[[Image~~:~~1_2_2_5_b_ss1~~.~~jpg\|~~center~~\|300px]]~~	+	<center>{{:2.2.5b - Solution - The line y = -3x + 1 through the point (1,-2)}}</center>

Markus.bez — Tue, 09 Jun 2009 09:34:10 GMT

← Nächstältere Version		Version vom 09:34, 9. Jun. 2009
Zeile 1:		Zeile 1:
-	Nachdem wir wissen dass die Steigung <math>-3</math> ist, haben wir ~~dass~~	+	Nachdem wir wissen, dass die Steigung <math>-3</math> ist, haben wir

	{{Abgesetzte Formel\|\|<math>y=-3x+m\,,</math>}}		{{Abgesetzte Formel\|\|<math>y=-3x+m\,,</math>}}
Zeile 7:		Zeile 7:
	{{Abgesetzte Formel\|\|<math>-2=-3\cdot 1+m\,,</math>}}		{{Abgesetzte Formel\|\|<math>-2=-3\cdot 1+m\,,</math>}}

-	~~Welches~~ uns <math>m=1</math> ~~gibt~~.	+	was uns <math>m=1</math> liefert.

	Also ist die Gleichung der Gerade <math>y=-3x+1</math>.		Also ist die Gleichung der Gerade <math>y=-3x+1</math>.

Martin — Thu, 12 Mar 2009 17:27:10 GMT

← Nächstältere Version		Version vom 17:27, 12. Mär. 2009
Zeile 1:		Zeile 1:
-	~~Because the straight line is to have a slope of~~ <math>-3</math>, ~~its equation can be written as~~	+	Nachdem wir wissen dass die Steigung <math>-3</math> ist, haben wir dass

	{{Abgesetzte Formel\|\|<math>y=-3x+m\,,</math>}}		{{Abgesetzte Formel\|\|<math>y=-3x+m\,,</math>}}

-	~~where~~ ''m'' ~~is a constant~~. ~~If the line is also to pass through the point~~ (''x'',''y'') = (1,-2), ~~the point must satisfy the equation of the line,~~	+	wo ''m'' noch bestimmt werden muss. Aber nachdem die Gerade durch den Punkt (''x'',''y'') = (1,-2) geht, muss dieser Punkt die Gleichung der Gerade erfüllen.

	{{Abgesetzte Formel\|\|<math>-2=-3\cdot 1+m\,,</math>}}		{{Abgesetzte Formel\|\|<math>-2=-3\cdot 1+m\,,</math>}}

-	~~which gives that~~ <math>m=1</math>.	+	Welches uns <math>m=1</math> gibt.

-	~~The answer is thus that the equation of the line is~~ <math>y=-3x+1</math>.	+	Also ist die Gleichung der Gerade <math>y=-3x+1</math>.


	[[Image:1_2_2_5_b_ss1.jpg\|center\|300px]]		[[Image:1_2_2_5_b_ss1.jpg\|center\|300px]]

Tekbot — Wed, 22 Oct 2008 13:57:45 GMT

hat „Solution 2.2:5b“ nach „Lösung 2.2:5b“ verschoben: Robot: moved page

← Nächstältere Version

Version vom 13:57, 22. Okt. 2008

Tekbot — Wed, 22 Oct 2008 08:28:38 GMT

Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel)

← Nächstältere Version		Version vom 08:28, 22. Okt. 2008
Zeile 1:		Zeile 1:
	Because the straight line is to have a slope of <math>-3</math>, its equation can be written as		Because the straight line is to have a slope of <math>-3</math>, its equation can be written as

-	{{~~Displayed math~~\|\|<math>y=-3x+m\,,</math>}}	+	{{Abgesetzte Formel\|\|<math>y=-3x+m\,,</math>}}

	where ''m'' is a constant. If the line is also to pass through the point (''x'',''y'') = (1,-2), the point must satisfy the equation of the line,		where ''m'' is a constant. If the line is also to pass through the point (''x'',''y'') = (1,-2), the point must satisfy the equation of the line,

-	{{~~Displayed math~~\|\|<math>-2=-3\cdot 1+m\,,</math>}}	+	{{Abgesetzte Formel\|\|<math>-2=-3\cdot 1+m\,,</math>}}

	which gives that <math>m=1</math>.		which gives that <math>m=1</math>.

Tek — Wed, 24 Sep 2008 12:28:56 GMT

← Nächstältere Version		Version vom 12:28, 24. Sep. 2008
Zeile 1:		Zeile 1:
-	Because the straight line is to have a ~~gradient~~ of	+	Because the straight line is to have a slope of <math>-3</math>, its equation can be written as
-	<math>-3</math>, its equation can be written as	+

		+	{{Displayed math\|\|<math>y=-3x+m\,,</math>}}

-	~~<math>~~y=-~~3x+m</math>~~	+	where ''m'' is a constant. If the line is also to pass through the point (''x'',''y'') = (1,-2), the point must satisfy the equation of the line,

		+	{{Displayed math\|\|<math>-2=-3\cdot 1+m\,,</math>}}

-	~~where~~	+	which gives that <math>m=1</math>.
-	<math>m~~</math>~~	+
-	~~is a constant. If the line is also to pass through the point~~	+
-	~~<math>\left( x \right.,\left. y \right)~~=~~\left(~~ 1 ~~\right.,\left. -2 \right)~~</math>~~, the point~~	+
-	~~must satisfy the equation of the line~~	+

		+	The answer is thus that the equation of the line is <math>y=-3x+1</math>.

-	<math>-2=-3\centerdot 1+m</math>
-
-
-	which gives that
-	<math>m=1</math>.
-
-	The answer is thus that the equation of the line is
-	<math>y=-3x+1</math>.
-
-
-	{{NAVCONTENT_START}}

	[[Image:1_2_2_5_b_ss1.jpg\|center\|300px]]		[[Image:1_2_2_5_b_ss1.jpg\|center\|300px]]
-	{{NAVCONTENT_STOP}}

Ian — Thu, 18 Sep 2008 09:13:06 GMT

← Nächstältere Version		Version vom 09:13, 18. Sep. 2008
Zeile 1:		Zeile 1:
		+	Because the straight line is to have a gradient of
		+	<math>-3</math>, its equation can be written as
		+
		+
		+	<math>y=-3x+m</math>
		+
		+
		+	where
		+	<math>m</math>
		+	is a constant. If the line is also to pass through the point
		+	<math>\left( x \right.,\left. y \right)=\left( 1 \right.,\left. -2 \right)</math>, the point
		+	must satisfy the equation of the line
		+
		+
		+	<math>-2=-3\centerdot 1+m</math>
		+
		+
		+	which gives that
		+	<math>m=1</math>.
		+
		+	The answer is thus that the equation of the line is
		+	<math>y=-3x+1</math>.
		+
		+
	{{NAVCONTENT_START}}		{{NAVCONTENT_START}}
-	~~<center> [[Image:2_2_5b.gif]] </center>~~	+
	[[Image:1_2_2_5_b_ss1.jpg\|center\|300px]]		[[Image:1_2_2_5_b_ss1.jpg\|center\|300px]]
	{{NAVCONTENT_STOP}}		{{NAVCONTENT_STOP}}

Tekbot — Tue, 09 Sep 2008 08:47:23 GMT

← Nächstältere Version

Version vom 08:47, 9. Sep. 2008

Tekbot — Thu, 21 Aug 2008 06:40:49 GMT

Robot: Automated text replacement (-[[Bild: +[[Image:)

Madde — Thu, 14 Aug 2008 15:20:09 GMT