Lösung 1.1:2c - Versionsgeschichte

Tekbot: hat „Solution 1.1:2c“ nach „Lösung 1.1:2c“ verschoben: Robot: moved page

Tekbot — Wed, 22 Oct 2008 13:16:44 GMT

hat „Solution 1.1:2c“ nach „Lösung 1.1:2c“ verschoben: Robot: moved page

← Nächstältere Version

Version vom 13:16, 22. Okt. 2008

Martin um 11:48, 18. Okt. 2008

Martin — Sat, 18 Oct 2008 11:48:19 GMT

← Nächstältere Version		Version vom 11:48, 18. Okt. 2008
Zeile 1:		Zeile 1:
	{{NAVCONTENT_START}}		{{NAVCONTENT_START}}
-	~~We can divide up the whole expression into two separate parts~~	+	Der Ausdruck besteht aus zwei Termen
	<center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,}</math></center>		<center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,}</math></center>
-	~~which we first calculate and then combine~~.	+	die wir einzeln berechnen und dann addieren.
	{{NAVCONTENT_STEP}}		{{NAVCONTENT_STEP}}
-	~~The first part of the expression equals~~	+	Der erste Term ist
	<center><math>3\cdot(-7) = -21</math></center>		<center><math>3\cdot(-7) = -21</math></center>
	{{NAVCONTENT_STEP}}		{{NAVCONTENT_STEP}}
-	~~whilst the second expression becomes.~~	+	und der zweite Term ist
	<center><math>4\cdot(6-5) = 4\cdot 1 = 4\,</math>.</center>		<center><math>4\cdot(6-5) = 4\cdot 1 = 4\,</math>.</center>
	{{NAVCONTENT_STEP}}		{{NAVCONTENT_STEP}}
-	~~Combining, we obtain~~	+	Addition der beiden Termen ergibt
	<center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,} = \bbox[#FFEEAA;,1.5pt]{\,-21\,}-\bbox[#FFEEAA;,1.5pt]{\,4\,} = -25\,</math>.</center>		<center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,} = \bbox[#FFEEAA;,1.5pt]{\,-21\,}-\bbox[#FFEEAA;,1.5pt]{\,4\,} = -25\,</math>.</center>
	{{NAVCONTENT_STOP}}		{{NAVCONTENT_STOP}}
	<!--<center> [[Image:1_1_2c.gif]] </center> -->		<!--<center> [[Image:1_1_2c.gif]] </center> -->

Ian um 13:13, 13. Sep. 2008

Ian — Sat, 13 Sep 2008 13:13:07 GMT

← Nächstältere Version		Version vom 13:13, 13. Sep. 2008
Zeile 1:		Zeile 1:
	{{NAVCONTENT_START}}		{{NAVCONTENT_START}}
-	~~Hela uttrycket kan vi dela upp i två delar~~	+	We can divide up the whole expression into two separate parts
	<center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,}</math></center>		<center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,}</math></center>
-	~~som vi kan räkna ut separat och sedan subtrahera från varandra~~.	+	which we first calculate and then combine.
	{{NAVCONTENT_STEP}}		{{NAVCONTENT_STEP}}
-	~~Det första deluttrycket är lika med~~	+	The first part of the expression equals
	<center><math>3\cdot(-7) = -21</math></center>		<center><math>3\cdot(-7) = -21</math></center>
	{{NAVCONTENT_STEP}}		{{NAVCONTENT_STEP}}
-	~~medan det andra deluttrycket blir~~	+	whilst the second expression becomes.
	<center><math>4\cdot(6-5) = 4\cdot 1 = 4\,</math>.</center>		<center><math>4\cdot(6-5) = 4\cdot 1 = 4\,</math>.</center>
	{{NAVCONTENT_STEP}}		{{NAVCONTENT_STEP}}
-	~~Sammantaget får vi~~	+	Combining, we obtain
	<center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,} = \bbox[#FFEEAA;,1.5pt]{\,-21\,}-\bbox[#FFEEAA;,1.5pt]{\,4\,} = -25\,</math>.</center>		<center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,} = \bbox[#FFEEAA;,1.5pt]{\,-21\,}-\bbox[#FFEEAA;,1.5pt]{\,4\,} = -25\,</math>.</center>
	{{NAVCONTENT_STOP}}		{{NAVCONTENT_STOP}}
	<!--<center> [[Image:1_1_2c.gif]] </center> -->		<!--<center> [[Image:1_1_2c.gif]] </center> -->

Tekbot: Lösning 1.1:2c moved to Solution 1.1:2c: Robot: moved page

Tekbot — Tue, 09 Sep 2008 08:06:23 GMT

Lösning 1.1:2c moved to Solution 1.1:2c: Robot: moved page

← Nächstältere Version

Version vom 08:06, 9. Sep. 2008

Tekbot: Robot: Automated text replacement (-[[Bild: +[[Image:)

Tekbot — Thu, 21 Aug 2008 06:20:39 GMT

Robot: Automated text replacement (-[[Bild: +[[Image:)

← Nächstältere Version		Version vom 06:20, 21. Aug. 2008
Zeile 13:		Zeile 13:
	<center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,} = \bbox[#FFEEAA;,1.5pt]{\,-21\,}-\bbox[#FFEEAA;,1.5pt]{\,4\,} = -25\,</math>.</center>		<center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,} = \bbox[#FFEEAA;,1.5pt]{\,-21\,}-\bbox[#FFEEAA;,1.5pt]{\,4\,} = -25\,</math>.</center>
	{{NAVCONTENT_STOP}}		{{NAVCONTENT_STOP}}
-	<!--<center> [[~~Bild~~:1_1_2c.gif]] </center> -->	+	<!--<center> [[Image:1_1_2c.gif]] </center> -->

Tek um 07:30, 29. Apr. 2008

Tek — Tue, 29 Apr 2008 07:30:58 GMT

← Nächstältere Version		Version vom 07:30, 29. Apr. 2008
Zeile 1:		Zeile 1:
	{{NAVCONTENT_START}}		{{NAVCONTENT_START}}
-	<center> [[~~Bild:1_1_2c~~.~~gif~~]] </center>	+	Hela uttrycket kan vi dela upp i två delar
		+	<center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,}</math></center>
		+	som vi kan räkna ut separat och sedan subtrahera från varandra.
		+	{{NAVCONTENT_STEP}}
		+	Det första deluttrycket är lika med
		+	<center><math>3\cdot(-7) = -21</math></center>
		+	{{NAVCONTENT_STEP}}
		+	medan det andra deluttrycket blir
		+	<center><math>4\cdot(6-5) = 4\cdot 1 = 4\,</math>.</center>
		+	{{NAVCONTENT_STEP}}
		+	Sammantaget får vi
		+	<center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,} = \bbox[#FFEEAA;,1.5pt]{\,-21\,}-\bbox[#FFEEAA;,1.5pt]{\,4\,} = -25\,</math>.</center>
	{{NAVCONTENT_STOP}}		{{NAVCONTENT_STOP}}
		+	<!--<center> [[Bild:1_1_2c.gif]] </center> -->

Lina um 11:00, 20. Mär. 2008

Lina — Thu, 20 Mar 2008 11:00:32 GMT

← Nächstältere Version		Version vom 11:00, 20. Mär. 2008
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	<center> [[Bild:1_1_2c.gif]] </center>		<center> [[Bild:1_1_2c.gif]] </center>
-
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Lina — Thu, 20 Mar 2008 10:56:14 GMT

Ny sida: {{NAVCONTENT_START}} <center> Bild:1_1_2c.gif </center> {{NAVCONTENT_STOP}}

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