<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/css" href="http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/skins/common/feed.css?97"?>
<feed xmlns="http://www.w3.org/2005/Atom" xml:lang="de">
		<id>http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php?action=history&amp;feed=atom&amp;title=L%C3%B6sung_5.2%3A1b</id>
		<title>Lösung 5.2:1b - Versionsgeschichte</title>
		<link rel="self" type="application/atom+xml" href="http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php?action=history&amp;feed=atom&amp;title=L%C3%B6sung_5.2%3A1b"/>
		<link rel="alternate" type="text/html" href="http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php?title=L%C3%B6sung_5.2:1b&amp;action=history"/>
		<updated>2026-06-17T16:33:51Z</updated>
		<subtitle>Versionsgeschichte für diese Seite in Online Mathematik Brückenkurs 1</subtitle>
		<generator>MediaWiki 1.11.1</generator>

	<entry>
		<id>http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php?title=L%C3%B6sung_5.2:1b&amp;diff=9749&amp;oldid=prev</id>
		<title>Markus.bez: Uebersetzung</title>
		<link rel="alternate" type="text/html" href="http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php?title=L%C3%B6sung_5.2:1b&amp;diff=9749&amp;oldid=prev"/>
				<updated>2009-08-10T09:11:45Z</updated>
		
		<summary type="html">&lt;p&gt;Uebersetzung&lt;/p&gt;

			&lt;table style=&quot;background-color: white; color:black;&quot;&gt;
			&lt;col class='diff-marker' /&gt;
			&lt;col class='diff-content' /&gt;
			&lt;col class='diff-marker' /&gt;
			&lt;col class='diff-content' /&gt;
			&lt;tr&gt;
				&lt;td colspan='2' style=&quot;background-color: white; color:black;&quot;&gt;← Nächstältere Version&lt;/td&gt;
				&lt;td colspan='2' style=&quot;background-color: white; color:black;&quot;&gt;Version vom 09:11, 10. Aug. 2009&lt;/td&gt;
			&lt;/tr&gt;
		&lt;tr&gt;&lt;td colspan=&quot;2&quot; class=&quot;diff-lineno&quot;&gt;Zeile 1:&lt;/td&gt;
&lt;td colspan=&quot;2&quot; class=&quot;diff-lineno&quot;&gt;Zeile 1:&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td class='diff-marker'&gt;-&lt;/td&gt;&lt;td style=&quot;background: #ffa; color:black; font-size: smaller;&quot;&gt;&lt;div&gt;&lt;del style=&quot;color: red; font-weight: bold; text-decoration: none;&quot;&gt;Squaring both sides of an equation can introduce more (spurious) solutions&lt;/del&gt;. &lt;del style=&quot;color: red; font-weight: bold; text-decoration: none;&quot;&gt;The equation to the right could have solutions that the equation to the left is lacking&lt;/del&gt;. &lt;del style=&quot;color: red; font-weight: bold; text-decoration: none;&quot;&gt;You should use the &lt;/del&gt;&amp;lt;math&amp;gt;\Rightarrow&amp;lt;/math&amp;gt; &lt;del style=&quot;color: red; font-weight: bold; text-decoration: none;&quot;&gt;arrow to indicate this&lt;/del&gt;.&lt;/div&gt;&lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;background: #cfc; color:black; font-size: smaller;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;color: red; font-weight: bold; text-decoration: none;&quot;&gt;Quadrieren beider Seiten einer Gleichung kann Scheinlösungen erzeugen&lt;/ins&gt;. &lt;ins style=&quot;color: red; font-weight: bold; text-decoration: none;&quot;&gt;Die Gleichung auf der rechten Seite kann deshalb mehr Gleichungen haben als die linke Seite&lt;/ins&gt;. &lt;ins style=&quot;color: red; font-weight: bold; text-decoration: none;&quot;&gt;Deshalb verwendet man hier &lt;/ins&gt;&amp;lt;math&amp;gt;\Rightarrow&amp;lt;/math&amp;gt;.&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;/table&gt;</summary>
		<author><name>Markus.bez</name></author>	</entry>

	<entry>
		<id>http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php?title=L%C3%B6sung_5.2:1b&amp;diff=8745&amp;oldid=prev</id>
		<title>Tek: Die Seite wurde neu angelegt: Squaring both sides of an equation can introduce more (spurious) solutions. The equation to the right could have solutions that the equation to the left is lacking. You...</title>
		<link rel="alternate" type="text/html" href="http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php?title=L%C3%B6sung_5.2:1b&amp;diff=8745&amp;oldid=prev"/>
				<updated>2009-04-06T07:47:35Z</updated>
		
		<summary type="html">&lt;p&gt;Die Seite wurde neu angelegt: Squaring both sides of an equation can introduce more (spurious) solutions. The equation to the right could have solutions that the equation to the left is lacking. You...&lt;/p&gt;
&lt;p&gt;&lt;b&gt;Neue Seite&lt;/b&gt;&lt;/p&gt;&lt;div&gt;Squaring both sides of an equation can introduce more (spurious) solutions. The equation to the right could have solutions that the equation to the left is lacking. You should use the &amp;lt;math&amp;gt;\Rightarrow&amp;lt;/math&amp;gt; arrow to indicate this.&lt;/div&gt;</summary>
		<author><name>Tek</name></author>	</entry>

	</feed>