Lösung 4.2:2a - Versionsgeschichte

Tek: Replaced figure with metapost figure

2009-08-20T14:30:50Z

Replaced figure with metapost figure

← Nächstältere Version		Version vom 14:30, 20. Aug. 2009
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	{\| width="100%"		{\| width="100%"
	\| width="50%" align="center"\|<math>\tan v = 2/5</math>		\| width="50%" align="center"\|<math>\tan v = 2/5</math>
-	\| width="50%" align="left"\|~~[[Image~~:~~4_2_2_a_de~~.~~gif]]~~	+	\| width="50%" align="left"\|{{:4.2.2a - Solution - A right triangle with the legs labeled}}
	\|}		\|}

	Dies ist eine Trigonometrische Gleichung für ''v''.		Dies ist eine Trigonometrische Gleichung für ''v''.

2009-07-30T15:46:53Z

← Nächstältere Version		Version vom 15:46, 30. Jul. 2009
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	{\| width="100%"		{\| width="100%"
	\| width="50%" align="center"\|<math>\tan v = 2/5</math>		\| width="50%" align="center"\|<math>\tan v = 2/5</math>
-	\| width="50%" align="left"\|[[Image:~~4_2_2_a~~.gif]]	+	\| width="50%" align="left"\|[[Image:4_2_2_a_de.gif]]
	\|}		\|}

	Dies ist eine Trigonometrische Gleichung für ''v''.		Dies ist eine Trigonometrische Gleichung für ''v''.

2009-06-18T09:57:04Z

← Nächstältere Version		Version vom 09:57, 18. Jun. 2009
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-	Wir ~~wissen~~ die Längen der Katheten im Dreieck, ~~und~~ also können wir den Tangens ~~für den Winkel~~ ''w'' ~~in den~~ Katheten ausdrücken,	+	Wir kennen die Längen der Katheten im Dreieck, also können wir den Tangens des Winkels ''w'' durch die Katheten ausdrücken:

	{\| width="100%"		{\| width="100%"
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	\|}		\|}

-	Dies ist eine Trigonometrische Gleichung ~~die~~ ''v'' ~~erfüllt~~.	+	Dies ist eine Trigonometrische Gleichung für ''v''.

2009-04-04T12:02:26Z

← Nächstältere Version		Version vom 12:02, 4. Apr. 2009
Zeile 1:		Zeile 1:
-	~~The opposite and adjacent are given~~ in ~~the right-angled triangle and this means that the value of the tangent for the angle can be determined as the quotient between the opposite and the adjacent:~~	+	Wir wissen die Längen der Katheten im Dreieck, und also können wir den Tangens für den Winkel ''w'' in den Katheten ausdrücken,

	{\| width="100%"		{\| width="100%"
Zeile 6:		Zeile 6:
	\|}		\|}

-	~~At the same time, this is a trigonometric equation for the angle~~ ''v''.	+	Dies ist eine Trigonometrische Gleichung die ''v'' erfüllt.
-		+
-		+
-	~~Note: In the chapter on "Trigonometric equations", we will investigate more closely how to solve equations of this type~~.	+

2008-10-22T14:52:04Z

hat „Solution 4.2:2a“ nach „Lösung 4.2:2a“ verschoben: Robot: moved page

← Nächstältere Version

Version vom 14:52, 22. Okt. 2008

2008-10-10T12:16:06Z

← Nächstältere Version		Version vom 12:16, 10. Okt. 2008
Zeile 1:		Zeile 1:
	The opposite and adjacent are given in the right-angled triangle and this means that the value of the tangent for the angle can be determined as the quotient between the opposite and the adjacent:		The opposite and adjacent are given in the right-angled triangle and this means that the value of the tangent for the angle can be determined as the quotient between the opposite and the adjacent:

		+	{\| width="100%"
		+	\| width="50%" align="center"\|<math>\tan v = 2/5</math>
		+	\| width="50%" align="left"\|[[Image:4_2_2_a.gif]]
		+	\|}

-	~~<math>\text{tan }~~v~~\text{ }={2}/{5}\;~</math>~~	+	At the same time, this is a trigonometric equation for the angle ''v''.


-	~~[[Image:4_2_2_a.gif\|center]]~~	+	Note: In the chapter on "Trigonometric equations", we will investigate more closely how to solve equations of this type.
-		+
-	~~At the same time, this is a trigonometric equation for the angle~~	+
-	~~<math>v</math>.~~	+
-		+
-	~~NOTE~~: In the chapter on "Trigonometric equations", we will investigate more closely how to solve equations of this type.	+

2008-10-10T09:09:29Z

← Nächstältere Version		Version vom 09:09, 10. Okt. 2008
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-	{{~~NAVCONTENT_START~~}}	+	The opposite and adjacent are given in the right-angled triangle and this means that the value of the tangent for the angle can be determined as the quotient between the opposite and the adjacent:
-	~~<center> [[Image:4_2_2a.gif]]~~ </~~center~~>	+
-	~~{{NAVCONTENT_STOP}}~~	+
		+	<math>\text{tan }v\text{ }={2}/{5}\;~</math>
		+
		+
	[[Image:4_2_2_a.gif\|center]]		[[Image:4_2_2_a.gif\|center]]
		+
		+	At the same time, this is a trigonometric equation for the angle
		+	<math>v</math>.
		+
		+	NOTE: In the chapter on "Trigonometric equations", we will investigate more closely how to solve equations of this type.

2008-09-09T09:41:43Z

← Nächstältere Version

Version vom 09:41, 9. Sep. 2008

2008-08-21T07:07:59Z

Robot: Automated text replacement (-[[Bild: +[[Image:)

2008-08-15T14:08:49Z