Lösung 4.1:6b - Versionsgeschichte

Tek um 08:09, 20. Aug. 2009

2009-08-20T08:09:24Z

← Nächstältere Version		Version vom 08:09, 20. Aug. 2009
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-	<center>{{:2.2.5a - Solution - The circle (x - 1)² + (y - 2)² = 3}}</center>	+	<center>{{:4.1.6b - Solution - The circle (x - 1)² + (y - 2)² = 3}}</center>

2009-08-20T08:06:53Z

Replaced figure with metapost figure

← Nächstältere Version		Version vom 08:06, 20. Aug. 2009
Zeile 10:		Zeile 10:


-	~~[[Image~~:~~4_1_6_b~~.~~gif\|~~center]]	+	<center>{{:2.2.5a - Solution - The circle (x - 1)² + (y - 2)² = 3}}</center>

2009-06-16T13:47:55Z

← Nächstältere Version		Version vom 13:47, 16. Jun. 2009
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-	Wir vergleichen unsere Gleichung mit der allgemeinen Gleichung eines Kreises, wo (''a'',''b'') der Mittelpunkt, und ''r'' der Radius ist,	+	Wir vergleichen unsere Gleichung mit der allgemeinen Gleichung eines Kreises, wo (''a'',''b'') der Mittelpunkt, und ''r'' der Radius ist:

	{{Abgesetzte Formel\|\|<math>(x-a)^2 + (y-b)^2 = r^2\,\textrm{.}</math>}}		{{Abgesetzte Formel\|\|<math>(x-a)^2 + (y-b)^2 = r^2\,\textrm{.}</math>}}

-	In unseren Fall können wir die Gleichung ~~wie~~	+	In unseren Fall können wir die Gleichung als

	{{Abgesetzte Formel\|\|<math>(x-1)^2 + (y-2)^2 = (\sqrt{3})^2</math>}}		{{Abgesetzte Formel\|\|<math>(x-1)^2 + (y-2)^2 = (\sqrt{3})^2</math>}}

2009-04-02T18:02:34Z

← Nächstältere Version		Version vom 18:02, 2. Apr. 2009
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-	~~A quick way to interpret the equation is to compare it with the standard formula for the equation of a circle with centre at~~ (''a'',''b'') ~~and radius~~ ''r'',	+	Wir vergleichen unsere Gleichung mit der allgemeinen Gleichung eines Kreises, wo (''a'',''b'') der Mittelpunkt, und ''r'' der Radius ist,

	{{Abgesetzte Formel\|\|<math>(x-a)^2 + (y-b)^2 = r^2\,\textrm{.}</math>}}		{{Abgesetzte Formel\|\|<math>(x-a)^2 + (y-b)^2 = r^2\,\textrm{.}</math>}}

-	In ~~our case, we can write the equation as~~	+	In unseren Fall können wir die Gleichung wie

	{{Abgesetzte Formel\|\|<math>(x-1)^2 + (y-2)^2 = (\sqrt{3})^2</math>}}		{{Abgesetzte Formel\|\|<math>(x-1)^2 + (y-2)^2 = (\sqrt{3})^2</math>}}

-	~~and then we see that it describes a circle with centre at~~ (1,2) ~~and radius~~ <math>\sqrt{3}\,</math>.	+	schreiben. Also haben wir einen Kreis mit dem Mittelpunkt (1,2) und mit dem Radius <math>\sqrt{3}\,</math>.


	[[Image:4_1_6_b.gif\|center]]		[[Image:4_1_6_b.gif\|center]]

2008-10-22T14:47:24Z

hat „Solution 4.1:6b“ nach „Lösung 4.1:6b“ verschoben: Robot: moved page

← Nächstältere Version

Version vom 14:47, 22. Okt. 2008

2008-10-22T08:48:58Z

Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel)

← Nächstältere Version		Version vom 08:48, 22. Okt. 2008
Zeile 1:		Zeile 1:
	A quick way to interpret the equation is to compare it with the standard formula for the equation of a circle with centre at (''a'',''b'') and radius ''r'',		A quick way to interpret the equation is to compare it with the standard formula for the equation of a circle with centre at (''a'',''b'') and radius ''r'',

-	{{~~Displayed math~~\|\|<math>(x-a)^2 + (y-b)^2 = r^2\,\textrm{.}</math>}}	+	{{Abgesetzte Formel\|\|<math>(x-a)^2 + (y-b)^2 = r^2\,\textrm{.}</math>}}

	In our case, we can write the equation as		In our case, we can write the equation as

-	{{~~Displayed math~~\|\|<math>(x-1)^2 + (y-2)^2 = (\sqrt{3})^2</math>}}	+	{{Abgesetzte Formel\|\|<math>(x-1)^2 + (y-2)^2 = (\sqrt{3})^2</math>}}

	and then we see that it describes a circle with centre at (1,2) and radius <math>\sqrt{3}\,</math>.		and then we see that it describes a circle with centre at (1,2) and radius <math>\sqrt{3}\,</math>.

2008-10-08T10:36:04Z

← Nächstältere Version		Version vom 10:36, 8. Okt. 2008
Zeile 1:		Zeile 1:
-	A quick way to interpret the equation is to compare it with the standard formula for the equation of a circle with centre at	+	A quick way to interpret the equation is to compare it with the standard formula for the equation of a circle with centre at (''a'',''b'') and radius ''r'',
-	~~<math>\left~~( a ~~\right.~~,~~\left.~~ b ~~\right~~)~~</math>~~	+
-	and radius	+
-	~~<math>~~r~~</math>~~,	+
-		+
-		+
-	~~<math>\left( x-a \right)^{2}+\left( y-b \right)^{2}=r^{2}</math>~~	+

		+	{{Displayed math\|\|<math>(x-a)^2 + (y-b)^2 = r^2\,\textrm{.}</math>}}

	In our case, we can write the equation as		In our case, we can write the equation as

		+	{{Displayed math\|\|<math>(x-1)^2 + (y-2)^2 = (\sqrt{3})^2</math>}}

-	~~<math>\left~~( x-1 ~~\right)^{~~2~~}+\left( y-2 \right~~)~~^{2}=\left(~~ \sqrt{3} \~~right)^{2}~~</math>	+	and then we see that it describes a circle with centre at (1,2) and radius <math>\sqrt{3}\,</math>.


-	and then we see that it describes a circle with centre at
-	<math>\left( 1 \right.,\left. 2 \right)</math>
-	and radius
-
-
-	{{NAVCONTENT_START}}
	[[Image:4_1_6_b.gif\|center]]		[[Image:4_1_6_b.gif\|center]]
-
-	{{NAVCONTENT_STOP}}

2008-09-27T11:33:31Z

← Nächstältere Version		Version vom 11:33, 27. Sep. 2008
Zeile 1:		Zeile 1:
		+	A quick way to interpret the equation is to compare it with the standard formula for the equation of a circle with centre at
		+	<math>\left( a \right.,\left. b \right)</math>
		+	and radius
		+	<math>r</math>,
		+
		+
		+	<math>\left( x-a \right)^{2}+\left( y-b \right)^{2}=r^{2}</math>
		+
		+
		+	In our case, we can write the equation as
		+
		+
		+	<math>\left( x-1 \right)^{2}+\left( y-2 \right)^{2}=\left( \sqrt{3} \right)^{2}</math>
		+
		+
		+	and then we see that it describes a circle with centre at
		+	<math>\left( 1 \right.,\left. 2 \right)</math>
		+	and radius
		+
		+
	{{NAVCONTENT_START}}		{{NAVCONTENT_START}}
	[[Image:4_1_6_b.gif\|center]]		[[Image:4_1_6_b.gif\|center]]

-	<center> [[Image:4_1_6b.gif]] </center>
	{{NAVCONTENT_STOP}}		{{NAVCONTENT_STOP}}

2008-09-09T09:37:03Z

← Nächstältere Version

Version vom 09:37, 9. Sep. 2008

2008-08-21T07:05:39Z

Robot: Automated text replacement (-[[Bild: +[[Image:)