Lösung 3.3:5a - Versionsgeschichte

Markus.bez: Sprache und Formulierung

2009-06-12T11:01:51Z

Sprache und Formulierung

← Nächstältere Version		Version vom 11:01, 12. Jun. 2009
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-	ln ~~bedeutet der natürliche~~ Logarithmus, ~~mit der~~ Basis ''e''. Daher ist <math>\ln e = 1\,</math>. Zusammen mit ~~den~~ Logarithmengesetz <math>b\lg a=\lg a^b</math>, haben wir	+	<math>\ln</math> steht für den natürlichen Logarithmus, d.h. den Logarithmus zur Basis ''e''. Daher ist <math>\ln e = 1\,</math>. Zusammen mit dem Logarithmengesetz <math>b\lg a=\lg a^b</math> haben wir

	{{Abgesetzte Formel\|\|<math>\ln e^3 + \ln e^2 = 3\cdot\ln e + 2\cdot \ln e = 3\cdot 1 + 2\cdot 1 = 5\,\textrm{.}</math>}}		{{Abgesetzte Formel\|\|<math>\ln e^3 + \ln e^2 = 3\cdot\ln e + 2\cdot \ln e = 3\cdot 1 + 2\cdot 1 = 5\,\textrm{.}</math>}}

2009-03-26T20:45:09Z

← Nächstältere Version		Version vom 20:45, 26. Mär. 2009
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-	~~The notation~~ ln ~~is used for the logarithm with the natural base <math>~~e ~~= 2\textrm{~~.~~}7182818\ldots\,,</math> and we therefore have that~~ <math>\ln e = 1\,</math>~~, which together with the logarithm law,~~ <math>b\lg a=\lg a^b</math>, ~~gives that~~	+	ln bedeutet der natürliche Logarithmus, mit der Basis ''e''. Daher ist <math>\ln e = 1\,</math>. Zusammen mit den Logarithmengesetz <math>b\lg a=\lg a^b</math>, haben wir

	{{Abgesetzte Formel\|\|<math>\ln e^3 + \ln e^2 = 3\cdot\ln e + 2\cdot \ln e = 3\cdot 1 + 2\cdot 1 = 5\,\textrm{.}</math>}}		{{Abgesetzte Formel\|\|<math>\ln e^3 + \ln e^2 = 3\cdot\ln e + 2\cdot \ln e = 3\cdot 1 + 2\cdot 1 = 5\,\textrm{.}</math>}}

2008-10-22T14:37:24Z

hat „Solution 3.3:5a“ nach „Lösung 3.3:5a“ verschoben: Robot: moved page

← Nächstältere Version

Version vom 14:37, 22. Okt. 2008

2008-10-22T08:44:18Z

Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel)

← Nächstältere Version		Version vom 08:44, 22. Okt. 2008
Zeile 1:		Zeile 1:
	The notation ln is used for the logarithm with the natural base <math>e = 2\textrm{.}7182818\ldots\,,</math> and we therefore have that <math>\ln e = 1\,</math>, which together with the logarithm law, <math>b\lg a=\lg a^b</math>, gives that		The notation ln is used for the logarithm with the natural base <math>e = 2\textrm{.}7182818\ldots\,,</math> and we therefore have that <math>\ln e = 1\,</math>, which together with the logarithm law, <math>b\lg a=\lg a^b</math>, gives that

-	{{~~Displayed math~~\|\|<math>\ln e^3 + \ln e^2 = 3\cdot\ln e + 2\cdot \ln e = 3\cdot 1 + 2\cdot 1 = 5\,\textrm{.}</math>}}	+	{{Abgesetzte Formel\|\|<math>\ln e^3 + \ln e^2 = 3\cdot\ln e + 2\cdot \ln e = 3\cdot 1 + 2\cdot 1 = 5\,\textrm{.}</math>}}

2008-10-02T07:19:24Z

← Nächstältere Version		Version vom 07:19, 2. Okt. 2008
Zeile 1:		Zeile 1:
-	The notation ln is used for the logarithm with the natural base	+	The notation ln is used for the logarithm with the natural base <math>e = 2\textrm{.}7182818\ldots\,,</math> and we therefore have that <math>\ln e = 1\,</math>, which together with the logarithm law, <math>b\lg a=\lg a^b</math>, gives that
-	<math>e=~~\text{~~2}.\~~text~~{~~7182818}..~~.,</math>	+

-	~~and we therefore have that~~	+	{{Displayed math\|\|<math>\ln e^3 + \ln e^2 = 3\cdot\ln e + 2\cdot \ln e = 3\cdot 1 + 2\cdot 1 = 5\,\textrm{.}</math>}}
-	~~<math>\text~~{~~ln }e=\text~~{~~1}</~~math~~>, which together with the logarithm law,~~	+
-	~~<math>b\lg a=\lg a^{b}</math>, gives that~~	+
-		+
-		+
-		+
-	<math>\ln e^{3}+\ln e^{2}=3\~~centerdot~~ \ln e+2\~~centerdot~~ \ln e=3\~~centerdot~~ 1+2\~~centerdot~~ 1=5</math>	+

2008-09-26T08:19:46Z

← Nächstältere Version		Version vom 08:19, 26. Sep. 2008
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-	{{~~NAVCONTENT_START~~}}	+	The notation ln is used for the logarithm with the natural base
-	<~~center~~> ~~[[Image:3_3_5a.gif]]~~ </~~center~~>	+	<math>e=\text{2}.\text{7182818}...,</math>
-	{{~~NAVCONTENT_STOP}~~}	+
		+	and we therefore have that
		+	<math>\text{ln }e=\text{1}</math>, which together with the logarithm law,
		+	<math>b\lg a=\lg a^{b}</math>, gives that
		+
		+
		+
		+	<math>\ln e^{3}+\ln e^{2}=3\centerdot \ln e+2\centerdot \ln e=3\centerdot 1+2\centerdot 1=5</math>

2008-09-09T09:27:03Z

← Nächstältere Version

Version vom 09:27, 9. Sep. 2008

2008-08-21T07:00:39Z

Robot: Automated text replacement (-[[Bild: +[[Image:)

2008-04-02T09:51:15Z

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