Lösung 2.1:1h - Versionsgeschichte

Moni: Formulierung

2009-08-04T13:51:31Z

Formulierung

← Nächstältere Version		Version vom 13:51, 4. Aug. 2009
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-	~~Wie~~ erweitern ~~den~~ Quadrat <math> (a+b)^2=a^2+2ab+b^2 </math> mit der binomischen Formel, wo <math> a=5x^3 </math> und <math> b=3x^5 </math>,	+	Wir erweitern das Quadrat <math> (a+b)^2=a^2+2ab+b^2 </math> mit der binomischen Formel, wobei <math> a=5x^3 </math> und <math> b=3x^5 </math>,

	{{Abgesetzte Formel\|\|<math>\begin{align}		{{Abgesetzte Formel\|\|<math>\begin{align}
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	\end{align}</math>}}		\end{align}</math>}}

-	In der letzten Reihe haben wir die Terme umgeordnet sodass ~~die Terme~~ nach Exponent geordnet sind.	+	In der letzten Reihe haben wir die Terme umgeordnet, sodass sie nach Exponent geordnet sind.

2009-02-28T12:51:32Z

← Nächstältere Version		Version vom 12:51, 28. Feb. 2009
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-	~~We expand the quadratic with the squaring rule~~ <math> (a+b)^2=a^2+2ab+b^2 </math>, ~~where~~ <math> a=5x^3 </math> ~~and~~ <math> b=3x^5 </math>,	+	Wie erweitern den Quadrat <math> (a+b)^2=a^2+2ab+b^2 </math> mit der binomischen Formel, wo <math> a=5x^3 </math> und <math> b=3x^5 </math>,

	{{Abgesetzte Formel\|\|<math>\begin{align}		{{Abgesetzte Formel\|\|<math>\begin{align}
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	\end{align}</math>}}		\end{align}</math>}}

-	~~Note:~~ In ~~the last line, we have moved the terms around so that the highest order term, <math> 9x^{10} </math>, comes first, followed by terms of decreasing order~~.	+	In der letzten Reihe haben wir die Terme umgeordnet sodass die Terme nach Exponent geordnet sind.

2008-10-22T13:43:05Z

hat „Solution 2.1:1h“ nach „Lösung 2.1:1h“ verschoben: Robot: moved page

← Nächstältere Version

Version vom 13:43, 22. Okt. 2008

2008-10-22T08:21:28Z

Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel)

← Nächstältere Version		Version vom 08:21, 22. Okt. 2008
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	We expand the quadratic with the squaring rule <math> (a+b)^2=a^2+2ab+b^2 </math>, where <math> a=5x^3 </math> and <math> b=3x^5 </math>,		We expand the quadratic with the squaring rule <math> (a+b)^2=a^2+2ab+b^2 </math>, where <math> a=5x^3 </math> and <math> b=3x^5 </math>,

-	{{~~Displayed math~~\|\|<math>\begin{align}	+	{{Abgesetzte Formel\|\|<math>\begin{align}
	(5x^3 + 3x^5)^2 &= (5x^3)^2 +2\cdot 5x^3\cdot 3x^5 +(3x^5)^{2} \\[3pt]		(5x^3 + 3x^5)^2 &= (5x^3)^2 +2\cdot 5x^3\cdot 3x^5 +(3x^5)^{2} \\[3pt]
	&= 5^2x^{3\cdot 2} + 2\cdot 5\cdot 3\cdot x^{3+5}+ 3^2 x^{5\cdot 2}\\[3pt]		&= 5^2x^{3\cdot 2} + 2\cdot 5\cdot 3\cdot x^{3+5}+ 3^2 x^{5\cdot 2}\\[3pt]

2008-09-23T08:04:34Z

← Nächstältere Version		Version vom 08:04, 23. Sep. 2008
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-	~~{{NAVCONTENT_START}}~~	+	We expand the quadratic with the squaring rule <math> (a+b)^2=a^2+2ab+b^2 </math>, where <math> a=5x^3 </math> and <math> b=3x^5 </math>,
-	We expand the quadratic with the squaring rule <math> (a+b)^2=a^2+2ab+b^2 </math>, where <math> a=5x^3 </math> and <math> b=3x^5 </math>	+

		+	{{Displayed math\|\|<math>\begin{align}
		+	(5x^3 + 3x^5)^2 &= (5x^3)^2 +2\cdot 5x^3\cdot 3x^5 +(3x^5)^{2} \\[3pt]
		+	&= 5^2x^{3\cdot 2} + 2\cdot 5\cdot 3\cdot x^{3+5}+ 3^2 x^{5\cdot 2}\\[3pt]
		+	&= 25x^6 +30 x^8 +9x^{10}\\[3pt]
		+	&= 9x^{10} +30x^8 +25x^6\textrm{.}
		+	\end{align}</math>}}

-	~~<math> \qquad~~	+	Note: In the last line, we have moved the terms around so that the highest order term, <math> 9x^{10} </math>, comes first, followed by terms of decreasing order.
-	~~\begin{align}~~	+
-	~~(5x^3 + 3x^5)^2 &= (5x^3)^2 +2\cdot 5x^3\cdot 3x^5 +(3x^5)^{2} \\~~	+
-	~~&= 5^2x^{3\cdot 2} + 2\cdot 5\cdot 3\cdot x^{3+5}+ 3^2 x^{5\cdot 2}\\~~	+
-	~~&= 25x^6 +30 x^8 +9x^{10}\\~~	+
-	~~&= 9x^{10} +30x^8 +25x^6~~	+
-	~~\end{align}~~	+
-	~~</math>~~	+
-		+
-	~~NOTE~~: In the last line, we have moved the terms around so that the highest order term, <math> 9x^{10} </math>, comes first, followed by terms of decreasing order.	+
-	~~<!-- <center> [[Image:2_1_1h.gif]] </center>-->~~	+
-	~~{{NAVCONTENT_STOP}}~~	+

2008-09-09T08:32:43Z

← Nächstältere Version

Version vom 08:32, 9. Sep. 2008

2008-08-21T06:33:29Z

Robot: Automated text replacement (-[[Bild: +[[Image:)

← Nächstältere Version		Version vom 06:33, 21. Aug. 2008
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	NOTE: In the last line, we have moved the terms around so that the highest order term, <math> 9x^{10} </math>, comes first, followed by terms of decreasing order.		NOTE: In the last line, we have moved the terms around so that the highest order term, <math> 9x^{10} </math>, comes first, followed by terms of decreasing order.
-	<!-- <center> [[~~Bild~~:2_1_1h.gif]] </center>-->	+	<!-- <center> [[Image:2_1_1h.gif]] </center>-->
	{{NAVCONTENT_STOP}}		{{NAVCONTENT_STOP}}

2008-08-13T09:50:26Z

← Nächstältere Version		Version vom 09:50, 13. Aug. 2008
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	{{NAVCONTENT_START}}		{{NAVCONTENT_START}}
-	<center> [[Bild:2_1_1h.gif]] </center>	+	We expand the quadratic with the squaring rule <math> (a+b)^2=a^2+2ab+b^2 </math>, where <math> a=5x^3 </math> and <math> b=3x^5 </math>
		+
		+
		+	<math> \qquad
		+	\begin{align}
		+	(5x^3 + 3x^5)^2 &= (5x^3)^2 +2\cdot 5x^3\cdot 3x^5 +(3x^5)^{2} \\
		+	&= 5^2x^{3\cdot 2} + 2\cdot 5\cdot 3\cdot x^{3+5}+ 3^2 x^{5\cdot 2}\\
		+	&= 25x^6 +30 x^8 +9x^{10}\\
		+	&= 9x^{10} +30x^8 +25x^6
		+	\end{align}
		+	</math>
		+
		+	NOTE: In the last line, we have moved the terms around so that the highest order term, <math> 9x^{10} </math>, comes first, followed by terms of decreasing order.
		+	<!-- <center> [[Bild:2_1_1h.gif]] </center>-->
	{{NAVCONTENT_STOP}}		{{NAVCONTENT_STOP}}

2008-03-31T09:29:04Z

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