Lösung 1.3:4c - Versionsgeschichte

Markus.bez um 13:07, 8. Jun. 2009

2009-06-08T13:07:03Z

← Nächstältere Version		Version vom 13:07, 8. Jun. 2009
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-	Alle Potenzen haben dieselbe Basis (5), und wir ~~verwänden~~ daher ~~Die~~ Rechenregeln für Potenzen um den Ausdruck zu vereinfachen	+	Alle Potenzen haben dieselbe Basis (5), und wir verwenden daher die Rechenregeln für Potenzen, um den Ausdruck zu vereinfachen

	{{Abgesetzte Formel\|\|<math>\begin{align}		{{Abgesetzte Formel\|\|<math>\begin{align}

2008-10-29T12:34:07Z

← Nächstältere Version		Version vom 12:34, 29. Okt. 2008
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-	~~The whole expression consists of factors having a base of~~ 5 ~~so the power rules can be used to simplify the expression first~~	+	Alle Potenzen haben dieselbe Basis (5), und wir verwänden daher Die Rechenregeln für Potenzen um den Ausdruck zu vereinfachen

	{{Abgesetzte Formel\|\|<math>\begin{align}		{{Abgesetzte Formel\|\|<math>\begin{align}

2008-10-22T13:35:45Z

hat „Solution 1.3:4c“ nach „Lösung 1.3:4c“ verschoben: Robot: moved page

← Nächstältere Version

Version vom 13:35, 22. Okt. 2008

2008-10-22T08:18:08Z

Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel)

← Nächstältere Version		Version vom 08:18, 22. Okt. 2008
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	The whole expression consists of factors having a base of 5 so the power rules can be used to simplify the expression first		The whole expression consists of factors having a base of 5 so the power rules can be used to simplify the expression first

-	{{~~Displayed math~~\|\|<math>\begin{align}	+	{{Abgesetzte Formel\|\|<math>\begin{align}
	\frac{5^{12}}{5^{-4}}\cdot \bigl( 5^{2} \bigr)^{-6}		\frac{5^{12}}{5^{-4}}\cdot \bigl( 5^{2} \bigr)^{-6}
	&= \frac{5^{12}}{5^{-4}}\cdot 5^{2\cdot (-6)}\\[3pt]		&= \frac{5^{12}}{5^{-4}}\cdot 5^{2\cdot (-6)}\\[3pt]

2008-09-22T14:05:19Z

← Nächstältere Version		Version vom 14:05, 22. Sep. 2008
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-	The whole expression consists of factors having a base of	+	The whole expression consists of factors having a base of 5 so the power rules can be used to simplify the expression first
-	~~<math>~~5~~</math>;~~	+

-	~~so the power rules can be use to~~	+	{{Displayed math\|\|<math>\begin{align}
-	~~simplify the expression first:~~	+	\frac{5^{12}}{5^{-4}}\cdot \bigl( 5^{2} \bigr)^{-6}
-		+	&= \frac{5^{12}}{5^{-4}}\cdot 5^{2\cdot (-6)}\\[3pt]
-		+	&= \frac{5^{12}}{5^{-4}}\cdot 5^{-12}\\[3pt]
-	<math>\begin{align}	+	&= \frac{5^{12}\cdot 5^{-12}}{5^{-4}}\\[3pt]
-	& \frac{5^{12}}{5^{-4}}\~~centerdot~~ \~~left~~( 5^{2} \~~right~~)^{-6}=\frac{5^{12}}{5^{-4}}\~~centerdot~~ 5^{2\~~centerdot \left~~( -6 ~~\right~~)}=\frac{5^{12}}{5^{-4}}\~~centerdot~~ 5^{-12}=\frac{5^{12}\~~centerdot~~ 5^{-12}}{5^{-4}} \\	+	&= \frac{5^{12-12}}{5^{-4}}\\[3pt]
-	~~& \\~~	+	&= \frac{5^{0}}{5^{-4}}\\[3pt]
-	& =\frac{5^{12-12}}{5^{-4}}=\frac{5^{0}}{5^{-4}}=5^{0-~~\left~~( -4 ~~\right~~)}=5^{4}=5\~~centerdot~~ 5\~~centerdot~~ 5\~~centerdot~~ 5=625 \\	+	&= 5^{0-(-4)}\\[3pt]
-	\end{align}</math>	+	&= 5^{4}\\[3pt]
		+	&= 5\cdot 5\cdot 5\cdot 5\\[3pt]
		+	&= 625\,\textrm{.}
		+	\end{align}</math>}}

2008-09-15T11:50:45Z

← Nächstältere Version		Version vom 11:50, 15. Sep. 2008
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-	~~{{NAVCONTENT_START}}~~	+	The whole expression consists of factors having a base of
-	<~~center~~> ~~[[Image:1_3_4c.gif]]~~ </~~center~~>	+	<math>5</math>;
-	{{~~NAVCONTENT_STOP~~}}	+
		+	so the power rules can be use to
		+	simplify the expression first:
		+
		+
		+	<math>\begin{align}
		+	& \frac{5^{12}}{5^{-4}}\centerdot \left( 5^{2} \right)^{-6}=\frac{5^{12}}{5^{-4}}\centerdot 5^{2\centerdot \left( -6 \right)}=\frac{5^{12}}{5^{-4}}\centerdot 5^{-12}=\frac{5^{12}\centerdot 5^{-12}}{5^{-4}} \\
		+	& \\
		+	& =\frac{5^{12-12}}{5^{-4}}=\frac{5^{0}}{5^{-4}}=5^{0-\left( -4 \right)}=5^{4}=5\centerdot 5\centerdot 5\centerdot 5=625 \\
		+	\end{align}</math>

2008-09-09T08:25:23Z

← Nächstältere Version

Version vom 08:25, 9. Sep. 2008

2008-08-21T06:29:49Z

Robot: Automated text replacement (-[[Bild: +[[Image:)

2008-03-26T15:03:16Z

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