Lösung 1.1:2b - Versionsgeschichte

Moni: Rechtschreibung

2009-08-08T12:41:24Z

Rechtschreibung

← Nächstältere Version		Version vom 12:41, 8. Aug. 2009
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	:<math>3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5) = 3-((\bbox[#FFEEAA;,1.5pt]{\,3\,}+6)-5)</math>.		:<math>3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5) = 3-((\bbox[#FFEEAA;,1.5pt]{\,3\,}+6)-5)</math>.
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-	In den resultierenden Ausdruck berechnen wir jetzt die innerste ~~klammer~~.	+	In den resultierenden Ausdruck berechnen wir jetzt die innerste Klammer.
	:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-(\firstcbox{#FFEEAA;}{\,(3+6)\,}{9}-5)</math>		:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-(\firstcbox{#FFEEAA;}{\,(3+6)\,}{9}-5)</math>
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	:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-\secondcbox{#FFEEAA;}{\,(9-5)\,}{4}</math>		:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-\secondcbox{#FFEEAA;}{\,(9-5)\,}{4}</math>
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-	und wir haben schließlich einen Ausdruck ohne Klammern den wir direkt berechnen	+	und wir haben schließlich einen Ausdruck ohne Klammern den wir direkt berechnen können
	:<math>\phantom{3-((\firstcbox{#FFEEAA;}{\,(7-4)\,}{3}+6)-5)}{} = -1</math>.		:<math>\phantom{3-((\firstcbox{#FFEEAA;}{\,(7-4)\,}{3}+6)-5)}{} = -1</math>.
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	<!--<center> [[Image:1_1_2b.gif]] </center> -->		<!--<center> [[Image:1_1_2b.gif]] </center> -->

Tekbot: hat „Solution 1.1:2b“ nach „Lösung 1.1:2b“ verschoben: Robot: moved page

2008-10-22T13:16:24Z

hat „Solution 1.1:2b“ nach „Lösung 1.1:2b“ verschoben: Robot: moved page

← Nächstältere Version

Version vom 13:16, 22. Okt. 2008

Martin um 11:44, 18. Okt. 2008

2008-10-18T11:44:20Z

← Nächstältere Version		Version vom 11:44, 18. Okt. 2008
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-	~~When calculating, the innermost part of the expression should always be calculated first~~.	+	Wir berechnen die innerste Klammer zuerst.
	:<math>3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5) = 3-((\bbox[#FFEEAA;,1.5pt]{\,3\,}+6)-5)</math>.		:<math>3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5) = 3-((\bbox[#FFEEAA;,1.5pt]{\,3\,}+6)-5)</math>.
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-	In ~~the resulting expression we again pick out and calculate the innermost part~~	+	In den resultierenden Ausdruck berechnen wir jetzt die innerste klammer.
	:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-(\firstcbox{#FFEEAA;}{\,(3+6)\,}{9}-5)</math>		:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-(\firstcbox{#FFEEAA;}{\,(3+6)\,}{9}-5)</math>
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	:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-(\secondcbox{#FFEEAA;}{\,(3+6)\,}{9}-5)</math>.		:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-(\secondcbox{#FFEEAA;}{\,(3+6)\,}{9}-5)</math>.
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-	~~Now there is just one bracket to calculate~~	+	Jetzt besteht nurmehr eine Klammer zum berechnen
	:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-\firstcbox{#FFEEAA;}{\,(9-5)\,}{4}</math>		:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-\firstcbox{#FFEEAA;}{\,(9-5)\,}{4}</math>
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	:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-\secondcbox{#FFEEAA;}{\,(9-5)\,}{4}</math>		:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-\secondcbox{#FFEEAA;}{\,(9-5)\,}{4}</math>
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-	~~and now there is only an expression without brackets left to calculate~~	+	und wir haben schließlich einen Ausdruck ohne Klammern den wir direkt berechnen
	:<math>\phantom{3-((\firstcbox{#FFEEAA;}{\,(7-4)\,}{3}+6)-5)}{} = -1</math>.		:<math>\phantom{3-((\firstcbox{#FFEEAA;}{\,(7-4)\,}{3}+6)-5)}{} = -1</math>.
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	<!--<center> [[Image:1_1_2b.gif]] </center> -->		<!--<center> [[Image:1_1_2b.gif]] </center> -->

Ian um 13:10, 13. Sep. 2008

2008-09-13T13:10:40Z

← Nächstältere Version		Version vom 13:10, 13. Sep. 2008
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-	~~Först identifierar vi det innersta parentesuttrycket och beräknar detta~~	+	When calculating, the innermost part of the expression should always be calculated first.
	:<math>3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5) = 3-((\bbox[#FFEEAA;,1.5pt]{\,3\,}+6)-5)</math>.		:<math>3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5) = 3-((\bbox[#FFEEAA;,1.5pt]{\,3\,}+6)-5)</math>.
	{{NAVCONTENT_STEP}}		{{NAVCONTENT_STEP}}
-	~~I det uttryck som nu uppstår ringar vi in den innersta parentesen och beräknar den~~	+	In the resulting expression we again pick out and calculate the innermost part
	:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-(\firstcbox{#FFEEAA;}{\,(3+6)\,}{9}-5)</math>		:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-(\firstcbox{#FFEEAA;}{\,(3+6)\,}{9}-5)</math>
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	:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-(\secondcbox{#FFEEAA;}{\,(3+6)\,}{9}-5)</math>.		:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-(\secondcbox{#FFEEAA;}{\,(3+6)\,}{9}-5)</math>.
	{{NAVCONTENT_STEP}}		{{NAVCONTENT_STEP}}
-	~~Efter detta har vi bara en parentes kvar att räkna ut~~	+	Now there is just one bracket to calculate
	:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-\firstcbox{#FFEEAA;}{\,(9-5)\,}{4}</math>		:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-\firstcbox{#FFEEAA;}{\,(9-5)\,}{4}</math>
	{{NAVCONTENT_STEP}}		{{NAVCONTENT_STEP}}
	:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-\secondcbox{#FFEEAA;}{\,(9-5)\,}{4}</math>		:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-\secondcbox{#FFEEAA;}{\,(9-5)\,}{4}</math>
	{{NAVCONTENT_STEP}}		{{NAVCONTENT_STEP}}
-	~~vilket till slut ger ett uttryck utan parenteser som vi direkt kan räkna ut~~	+	and now there is only an expression without brackets left to calculate
	:<math>\phantom{3-((\firstcbox{#FFEEAA;}{\,(7-4)\,}{3}+6)-5)}{} = -1</math>.		:<math>\phantom{3-((\firstcbox{#FFEEAA;}{\,(7-4)\,}{3}+6)-5)}{} = -1</math>.
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	<!--<center> [[Image:1_1_2b.gif]] </center> -->		<!--<center> [[Image:1_1_2b.gif]] </center> -->

Tekbot: Lösning 1.1:2b moved to Solution 1.1:2b: Robot: moved page

2008-09-09T08:06:03Z

Lösning 1.1:2b moved to Solution 1.1:2b: Robot: moved page

← Nächstältere Version

Version vom 08:06, 9. Sep. 2008

Tekbot: Robot: Automated text replacement (-[[Bild: +[[Image:)

2008-08-21T06:20:19Z

Robot: Automated text replacement (-[[Bild: +[[Image:)

← Nächstältere Version		Version vom 06:20, 21. Aug. 2008
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	:<math>\phantom{3-((\firstcbox{#FFEEAA;}{\,(7-4)\,}{3}+6)-5)}{} = -1</math>.		:<math>\phantom{3-((\firstcbox{#FFEEAA;}{\,(7-4)\,}{3}+6)-5)}{} = -1</math>.
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-	<!--<center> [[~~Bild~~:1_1_2b.gif]] </center> -->	+	<!--<center> [[Image:1_1_2b.gif]] </center> -->

Tek um 07:29, 29. Apr. 2008

2008-04-29T07:29:24Z

← Nächstältere Version		Version vom 07:29, 29. Apr. 2008
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-	<~~center~~> [[~~Bild~~:~~1_1_2b~~.~~gif~~]] </~~center~~>	+	Först identifierar vi det innersta parentesuttrycket och beräknar detta
		+	:<math>3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5) = 3-((\bbox[#FFEEAA;,1.5pt]{\,3\,}+6)-5)</math>.
		+	{{NAVCONTENT_STEP}}
		+	I det uttryck som nu uppstår ringar vi in den innersta parentesen och beräknar den
		+	:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-(\firstcbox{#FFEEAA;}{\,(3+6)\,}{9}-5)</math>
		+	{{NAVCONTENT_STEP}}
		+	:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-(\secondcbox{#FFEEAA;}{\,(3+6)\,}{9}-5)</math>.
		+	{{NAVCONTENT_STEP}}
		+	Efter detta har vi bara en parentes kvar att räkna ut
		+	:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-\firstcbox{#FFEEAA;}{\,(9-5)\,}{4}</math>
		+	{{NAVCONTENT_STEP}}
		+	:<math>\phantom{3-((\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+6)-5)}{} = 3-\secondcbox{#FFEEAA;}{\,(9-5)\,}{4}</math>
		+	{{NAVCONTENT_STEP}}
		+	vilket till slut ger ett uttryck utan parenteser som vi direkt kan räkna ut
		+	:<math>\phantom{3-((\firstcbox{#FFEEAA;}{\,(7-4)\,}{3}+6)-5)}{} = -1</math>.
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Lina um 11:00, 20. Mär. 2008

2008-03-20T11:00:02Z

← Nächstältere Version		Version vom 11:00, 20. Mär. 2008
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2008-03-20T10:57:15Z

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