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Lösung 1.1:2a - Versionsgeschichte
2026-05-02T19:27:00Z
Versionsgeschichte für diese Seite in Online Mathematik Brückenkurs 1
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Moni: Rechtschreibung
2009-08-08T12:40:29Z
<p>Rechtschreibung</p>
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<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div>Der Ausdruck besteht aus zwei äußeren Klammern</div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div>Der Ausdruck besteht aus zwei äußeren Klammern<ins style="color: red; font-weight: bold; text-decoration: none;">,</ins></div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><center><math>\bbox[#FFEEAA;,1.5pt]{\,(3-(7-4))\,}\cdot\bbox[#FFEEAA;,1.5pt]{\,(6-5)\,}</math></center></div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><center><math>\bbox[#FFEEAA;,1.5pt]{\,(3-(7-4))\,}\cdot\bbox[#FFEEAA;,1.5pt]{\,(6-5)\,}</math></center></div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div>die wir zuerst einzeln berechnen<del style="color: red; font-weight: bold; text-decoration: none;">, </del>und danach mit einander multiplizieren. In der linken Klammer berechnen wir zuerst die innere Klammer</div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div>die wir zuerst einzeln berechnen und danach mit einander multiplizieren. In der linken Klammer berechnen wir zuerst die innere Klammer</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><center><math>(3-\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}) = (3-\bbox[#FFEEAA;,1.5pt]{\,3\,})</math></center></div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><center><math>(3-\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}) = (3-\bbox[#FFEEAA;,1.5pt]{\,3\,})</math></center></div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div>also ist die linke <del style="color: red; font-weight: bold; text-decoration: none;">klammer</del></div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div>also ist die linke <ins style="color: red; font-weight: bold; text-decoration: none;">Klammer</ins></div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><math>3-3=0</math>.</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><math>3-3=0</math>.</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STEP}}</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STEP}}</div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div>Der ganze Ausdruck ist <math>0</math> multipliziert mit <math>(6-5)</math>, <del style="color: red; font-weight: bold; text-decoration: none;">und </del>also ist der Ausdruck gleich <math>0</math>.</div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div>Der ganze Ausdruck ist <math>0</math> multipliziert mit <math>(6-5)</math>, <ins style="color: red; font-weight: bold; text-decoration: none;"> </ins>also ist der Ausdruck gleich <math>0</math>.</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STOP}}</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STOP}}</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><!--<center> [[Image:1_1_2a.gif]] </center> --></div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><!--<center> [[Image:1_1_2a.gif]] </center> --></div></td></tr>
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Moni
http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php?title=L%C3%B6sung_1.1:2a&diff=7055&oldid=prev
Tekbot: hat „Solution 1.1:2a“ nach „Lösung 1.1:2a“ verschoben: Robot: moved page
2008-10-22T13:16:04Z
<p>hat „<a href="/wikis/2009/bridgecourse1-TU-Berlin/index.php?title=Solution_1.1:2a&action=edit" class="new" title="Solution 1.1:2a">Solution 1.1:2a</a>“ nach „<a href="/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_1.1:2a" title="Lösung 1.1:2a">Lösung 1.1:2a</a>“ verschoben: Robot: moved page</p>
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<td colspan='2' style="background-color: white; color:black;">Version vom 13:16, 22. Okt. 2008</td>
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Tekbot
http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php?title=L%C3%B6sung_1.1:2a&diff=5933&oldid=prev
Martin um 11:36, 18. Okt. 2008
2008-10-18T11:36:51Z
<p></p>
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<td colspan='2' style="background-color: white; color:black;">Version vom 11:36, 18. Okt. 2008</td>
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<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><math>3-3=0</math>.</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><math>3-3=0</math>.</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STEP}}</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STEP}}</div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div>Der ganze Ausdruck ist <math>0</math> multipliziert mit <math>(6-5)</math>, und also ist der Ausdruck gleich 0.</div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div>Der ganze Ausdruck ist <math>0</math> multipliziert mit <math>(6-5)</math>, und also ist der Ausdruck gleich <ins style="color: red; font-weight: bold; text-decoration: none;"><math></ins>0<ins style="color: red; font-weight: bold; text-decoration: none;"></math></ins>.</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STOP}}</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STOP}}</div></td></tr>
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Martin
http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php?title=L%C3%B6sung_1.1:2a&diff=5932&oldid=prev
Martin um 11:36, 18. Okt. 2008
2008-10-18T11:36:16Z
<p></p>
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<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div><del style="color: red; font-weight: bold; text-decoration: none;">The expression consists of two brackets</del></div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><ins style="color: red; font-weight: bold; text-decoration: none;">Der Ausdruck besteht aus zwei äußeren Klammern</ins></div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><center><math>\bbox[#FFEEAA;,1.5pt]{\,(3-(7-4))\,}\cdot\bbox[#FFEEAA;,1.5pt]{\,(6-5)\,}</math></center></div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><center><math>\bbox[#FFEEAA;,1.5pt]{\,(3-(7-4))\,}\cdot\bbox[#FFEEAA;,1.5pt]{\,(6-5)\,}</math></center></div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div><del style="color: red; font-weight: bold; text-decoration: none;">which we can work out individually and then multiply together</del>.</div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><ins style="color: red; font-weight: bold; text-decoration: none;">die wir zuerst einzeln berechnen, und danach mit einander multiplizieren</ins>. In <ins style="color: red; font-weight: bold; text-decoration: none;">der linken Klammer berechnen wir zuerst die innere Klammer</ins></div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div>In <del style="color: red; font-weight: bold; text-decoration: none;">the expression in the first bracket, we calculate the inner bracket first</del></div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div></div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><center><math>(3-\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}) = (3-\bbox[#FFEEAA;,1.5pt]{\,3\,})</math></center></div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><center><math>(3-\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}) = (3-\bbox[#FFEEAA;,1.5pt]{\,3\,})</math></center></div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div><del style="color: red; font-weight: bold; text-decoration: none;">and obtain that the expression in the first bracket becomes</del></div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><ins style="color: red; font-weight: bold; text-decoration: none;">also ist die linke klammer</ins></div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><math>3-3=0</math>.</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><math>3-3=0</math>.</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STEP}}</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STEP}}</div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div><del style="color: red; font-weight: bold; text-decoration: none;">The complete expression is </del>0 <del style="color: red; font-weight: bold; text-decoration: none;">times </del><math>(6-5)</math>, <del style="color: red; font-weight: bold; text-decoration: none;">and since 0 times anything is always 0 the answer is </del>0.</div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><ins style="color: red; font-weight: bold; text-decoration: none;">Der ganze Ausdruck ist <math></ins>0<ins style="color: red; font-weight: bold; text-decoration: none;"></math> multipliziert mit </ins><math>(6-5)</math>, <ins style="color: red; font-weight: bold; text-decoration: none;">und also ist der Ausdruck gleich </ins>0.</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STOP}}</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STOP}}</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><!--<center> [[Image:1_1_2a.gif]] </center> --></div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><!--<center> [[Image:1_1_2a.gif]] </center> --></div></td></tr>
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Martin
http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php?title=L%C3%B6sung_1.1:2a&diff=5055&oldid=prev
Ian um 13:01, 13. Sep. 2008
2008-09-13T13:01:01Z
<p></p>
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<td colspan='2' style="background-color: white; color:black;">Version vom 13:01, 13. Sep. 2008</td>
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<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div><del style="color: red; font-weight: bold; text-decoration: none;">Uttrycket består av två parenteser</del></div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><ins style="color: red; font-weight: bold; text-decoration: none;">The expression consists of two brackets</ins></div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><center><math>\bbox[#FFEEAA;,1.5pt]{\,(3-(7-4))\,}\cdot\bbox[#FFEEAA;,1.5pt]{\,(6-5)\,}</math></center></div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><center><math>\bbox[#FFEEAA;,1.5pt]{\,(3-(7-4))\,}\cdot\bbox[#FFEEAA;,1.5pt]{\,(6-5)\,}</math></center></div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div><del style="color: red; font-weight: bold; text-decoration: none;">som vi kan räkna ut var för sig och sedan multiplicera ihop resultatet</del>.</div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><ins style="color: red; font-weight: bold; text-decoration: none;">which we can work out individually and then multiply together</ins>.</div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div><del style="color: red; font-weight: bold; text-decoration: none;">{{NAVCONTENT_STEP}}</del></div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><ins style="color: red; font-weight: bold; text-decoration: none;">In the expression in the first bracket, we calculate the inner bracket first</ins></div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div><del style="color: red; font-weight: bold; text-decoration: none;">I det första parentesuttrycket räknar vi först ut den inre parentesen</del></div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div></div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><center><math>(3-\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}) = (3-\bbox[#FFEEAA;,1.5pt]{\,3\,})</math></center></div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><center><math>(3-\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}) = (3-\bbox[#FFEEAA;,1.5pt]{\,3\,})</math></center></div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div><del style="color: red; font-weight: bold; text-decoration: none;">och får därför att det första parentesuttrycket blir </del><math>3-3=0</math>.</div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><ins style="color: red; font-weight: bold; text-decoration: none;">and obtain that the expression in the first bracket becomes</ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><math>3-3=0</math>.</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STEP}}</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STEP}}</div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div><del style="color: red; font-weight: bold; text-decoration: none;">Hela uttrycket är alltså lika med </del>0 <del style="color: red; font-weight: bold; text-decoration: none;">gånger </del><math>(6-5)</math>, <del style="color: red; font-weight: bold; text-decoration: none;">och eftersom </del>0 <del style="color: red; font-weight: bold; text-decoration: none;">gånger någonting alltid ger </del>0 <del style="color: red; font-weight: bold; text-decoration: none;">så blir </del>answer 0.</div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><ins style="color: red; font-weight: bold; text-decoration: none;">The complete expression is </ins>0 <ins style="color: red; font-weight: bold; text-decoration: none;">times </ins><math>(6-5)</math>, <ins style="color: red; font-weight: bold; text-decoration: none;">and since </ins>0 <ins style="color: red; font-weight: bold; text-decoration: none;">times anything is always </ins>0 <ins style="color: red; font-weight: bold; text-decoration: none;">the </ins>answer <ins style="color: red; font-weight: bold; text-decoration: none;">is </ins>0.</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STOP}}</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STOP}}</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><!--<center> [[Image:1_1_2a.gif]] </center> --></div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><!--<center> [[Image:1_1_2a.gif]] </center> --></div></td></tr>
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Ian
http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php?title=L%C3%B6sung_1.1:2a&diff=5010&oldid=prev
Tekbot: Robot: Automated text replacement (-svaret +answer)
2008-09-12T15:19:02Z
<p>Robot: Automated text replacement (-svaret +answer)</p>
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<td colspan='2' style="background-color: white; color:black;">Version vom 15:19, 12. Sep. 2008</td>
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<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>och får därför att det första parentesuttrycket blir <math>3-3=0</math>.</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>och får därför att det första parentesuttrycket blir <math>3-3=0</math>.</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STEP}}</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STEP}}</div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div>Hela uttrycket är alltså lika med 0 gånger <math>(6-5)</math>, och eftersom 0 gånger någonting alltid ger 0 så blir <del style="color: red; font-weight: bold; text-decoration: none;">svaret </del>0.</div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div>Hela uttrycket är alltså lika med 0 gånger <math>(6-5)</math>, och eftersom 0 gånger någonting alltid ger 0 så blir <ins style="color: red; font-weight: bold; text-decoration: none;">answer </ins>0.</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STOP}}</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STOP}}</div></td></tr>
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Tekbot
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Tekbot: Lösning 1.1:2a moved to Solution 1.1:2a: Robot: moved page
2008-09-09T08:05:43Z
<p><a href="/wikis/2009/bridgecourse1-TU-Berlin/index.php?title=L%C3%B6sning_1.1:2a&action=edit" class="new" title="Lösning 1.1:2a">Lösning 1.1:2a</a> moved to <a href="/wikis/2009/bridgecourse1-TU-Berlin/index.php?title=Solution_1.1:2a&action=edit" class="new" title="Solution 1.1:2a">Solution 1.1:2a</a>: Robot: moved page</p>
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<td colspan='2' style="background-color: white; color:black;">Version vom 08:05, 9. Sep. 2008</td>
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2008-08-21T06:19:59Z
<p>Robot: Automated text replacement (-[[Bild: +[[Image:)</p>
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<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>Hela uttrycket är alltså lika med 0 gånger <math>(6-5)</math>, och eftersom 0 gånger någonting alltid ger 0 så blir svaret 0.</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>Hela uttrycket är alltså lika med 0 gånger <math>(6-5)</math>, och eftersom 0 gånger någonting alltid ger 0 så blir svaret 0.</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STOP}}</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STOP}}</div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div><!--<center> [[<del style="color: red; font-weight: bold; text-decoration: none;">Bild</del>:1_1_2a.gif]] </center> --></div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><!--<center> [[<ins style="color: red; font-weight: bold; text-decoration: none;">Image</ins>:1_1_2a.gif]] </center> --></div></td></tr>
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http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php?title=L%C3%B6sung_1.1:2a&diff=1526&oldid=prev
Tek um 07:27, 29. Apr. 2008
2008-04-29T07:27:18Z
<p></p>
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<td colspan='2' style="background-color: white; color:black;">Version vom 07:27, 29. Apr. 2008</td>
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<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div><center> [[<del style="color: red; font-weight: bold; text-decoration: none;">Bild:1_1_2a</del>.<del style="color: red; font-weight: bold; text-decoration: none;">gif</del>]] </center></div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><ins style="color: red; font-weight: bold; text-decoration: none;">Uttrycket består av två parenteser</ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><center><ins style="color: red; font-weight: bold; text-decoration: none;"><math>\bbox</ins>[<ins style="color: red; font-weight: bold; text-decoration: none;">#FFEEAA;,1.5pt]{\,(3-(7-4))\,}\cdot\bbox</ins>[<ins style="color: red; font-weight: bold; text-decoration: none;">#FFEEAA;,1</ins>.<ins style="color: red; font-weight: bold; text-decoration: none;">5pt</ins>]<ins style="color: red; font-weight: bold; text-decoration: none;">{\,(6-5)\,}</math></center></ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><ins style="color: red; font-weight: bold; text-decoration: none;">som vi kan räkna ut var för sig och sedan multiplicera ihop resultatet.</ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><ins style="color: red; font-weight: bold; text-decoration: none;">{{NAVCONTENT_STEP}}</ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><ins style="color: red; font-weight: bold; text-decoration: none;">I det första parentesuttrycket räknar vi först ut den inre parentesen</ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><ins style="color: red; font-weight: bold; text-decoration: none;"><center><math>(3-\bbox[#FFEEAA;,1.5pt</ins>]<ins style="color: red; font-weight: bold; text-decoration: none;">{\,(7-4)\,}) = (3-\bbox[#FFEEAA;,1.5pt]{\,3\,})</math></ins></center></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><ins style="color: red; font-weight: bold; text-decoration: none;">och får därför att det första parentesuttrycket blir <math>3-3=0</math>.</ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><ins style="color: red; font-weight: bold; text-decoration: none;">{{NAVCONTENT_STEP}}</ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><ins style="color: red; font-weight: bold; text-decoration: none;">Hela uttrycket är alltså lika med 0 gånger <math>(6-5)</math>, och eftersom 0 gånger någonting alltid ger 0 så blir svaret 0.</ins></div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STOP}}</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>{{NAVCONTENT_STOP}}</div></td></tr>
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Lina um 10:59, 20. Mär. 2008
2008-03-20T10:59:50Z
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<td colspan='2' style="background-color: white; color:black;">Version vom 10:59, 20. Mär. 2008</td>
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Lina