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Antwort 1.2:5 - Versionsgeschichte
2026-05-02T23:38:36Z
Versionsgeschichte für diese Seite in Online Mathematik Brückenkurs 1
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Tekbot: hat „Answer 1.2:5“ nach „Antwort 1.2:5“ verschoben: Robot: moved page
2008-10-22T17:21:37Z
<p>hat „<a href="/wikis/2009/bridgecourse1-TU-Berlin/index.php?title=Answer_1.2:5&action=edit" class="new" title="Answer 1.2:5">Answer 1.2:5</a>“ nach „<a href="/wikis/2009/bridgecourse1-TU-Berlin/index.php/Antwort_1.2:5" title="Antwort 1.2:5">Antwort 1.2:5</a>“ verschoben: Robot: moved page</p>
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<td colspan='2' style="background-color: white; color:black;">← Nächstältere Version</td>
<td colspan='2' style="background-color: white; color:black;">Version vom 17:21, 22. Okt. 2008</td>
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Tekbot
http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php?title=Antwort_1.2:5&diff=2558&oldid=prev
Tekbot: Svar 1.2:5 moved to Answer 1.2:5: Robot: moved page
2008-09-08T14:29:22Z
<p><a href="/wikis/2009/bridgecourse1-TU-Berlin/index.php?title=Svar_1.2:5&action=edit" class="new" title="Svar 1.2:5">Svar 1.2:5</a> moved to <a href="/wikis/2009/bridgecourse1-TU-Berlin/index.php?title=Answer_1.2:5&action=edit" class="new" title="Answer 1.2:5">Answer 1.2:5</a>: Robot: moved page</p>
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<td colspan='2' style="background-color: white; color:black;">← Nächstältere Version</td>
<td colspan='2' style="background-color: white; color:black;">Version vom 14:29, 8. Sep. 2008</td>
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http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php?title=Antwort_1.2:5&diff=317&oldid=prev
Lina: Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%"| <math>\displaystyle \frac{105}{4}</math> |b) |width="33%"| <math>-5</math> |c) |width="33%"| <math>\displaystyle \frac{8}{55}</math> |}
2008-03-26T09:38:58Z
<p>Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%"| <math>\displaystyle \frac{105}{4}</math> |b) |width="33%"| <math>-5</math> |c) |width="33%"| <math>\displaystyle \frac{8}{55}</math> |}</p>
<p><b>Neue Seite</b></p><div>{| width="100%" cellspacing="10px"<br />
|a)<br />
|width="33%"| <math>\displaystyle \frac{105}{4}</math><br />
|b)<br />
|width="33%"| <math>-5</math><br />
|c)<br />
|width="33%"| <math>\displaystyle \frac{8}{55}</math><br />
|}</div>
Lina