Aus Online Mathematik Brückenkurs 1

Diese Aktion ist beschränkt auf Benutzer, die einer der Gruppen „Administratoren, approved“ angehören.

Quelltext dieser Seite:

The expression for the angle <math>\pi/2 - v</math> differs from <math>\pi/2</math> by as much as <math>-v</math> differs from <math>0</math>. This means that <math>\pi/2-v</math> makes the same angle with the positive ''y''-axis as <math>-v</math> makes with the positive ''x''-axis. {| align="center" | align="center" |[[Image:4_3_3_d-1.gif]] | width="20px"|&nbsp; | align="center" |[[Image:4_3_3_d-2.gif]] |- | align="center" |<small>Angle&nbsp;''v''</small> || | align="center" |<small>Angle&nbsp;π/2&nbsp;-&nbsp;''v''</small> |} Therefore, the angle <math>\pi/2 - v</math> has a ''y''-coordinate which is equal to the ''x''-coordinate for the angle ''v'', i.e. {{Displayed math||<math>\sin\Bigl(\frac{\pi}{2} - v\Bigr) = \cos v</math>}} and from exercise c, we know that <math>\cos v = \sqrt{1-a^2}\,</math>, {{Displayed math||<math>\sin\Bigl(\frac{\pi}{2}-v\Bigr) = \sqrt{1-a^2}\,\textrm{.}</math>}}

• 4.3.3d - Solution - The unit circle with angle v
• 4.3.3d - Solution - The unit circle with angle π/2 - v
• Vorlage:Abgesetzte Formel

Zurück zur Seite Hauptseite.