Answer 5.1:2

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
Current revision (14:31, 28 January 2009) (edit) (undo)
 
Line 1: Line 1:
{| width="100%" cellspacing="10px"
{| width="100%" cellspacing="10px"
|a)
|a)
-
|width="100%" | <nowiki><math></nowiki>3\times 4\pm 4<nowiki></math></nowiki>
+
|width="100%" | 3\times 4\pm 4
|-
|-
|b)
|b)
-
|width="100%" | <nowiki><math></nowiki>4x^2-\sqrt{x}<nowiki></math></nowiki>
+
|width="100%" | 4x^2-\sqrt{x}
|-
|-
|c)
|c)
-
|width="100%" | <nowiki><math></nowiki>4\times 3^n\ge n^3<nowiki></math></nowiki>
+
|width="100%" | 4\times 3^n\ge n^3
|-
|-
|d)
|d)
-
|width="100%" | <nowiki><math></nowiki>3-(5-2)=-(-3+5-2)<nowiki></math></nowiki>
+
|width="100%" | 3-(5-2)=-(-3+5-2)
|}
|}

Current revision

a) 3\times 4\pm 4
b) 4x^2-\sqrt{x}
c) 4\times 3^n\ge n^3
d) 3-(5-2)=-(-3+5-2)
Retrieved from "http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-ImperialCollege/index.php/Answer_5.1:2"