Answer 5.1:3
From Förberedande kurs i matematik 1
(Difference between revisions)
Lina (Talk | contribs)
(New page: {| width="100%" cellspacing="10px" |a) |width="50%" | <math>x^3y^2\left(\displaystyle \frac{1}{y} - \frac{1}{xy}+1\right)</math> |b) |width="50%" | <math>\left(x-y+\displ...)
Next diff →
Revision as of 13:12, 22 January 2009
a) | <math>x^3y^2\left(\displaystyle \frac{1}{y} - \frac{1}{xy}+1\right)</math> | b) | <math>\left(x-y+\displaystyle\frac{x^2}{y-x}\right) \left(\displaystyle\frac{y}{2x-y}-1\right)</math> |
c) | <math>\displaystyle\frac{a-b+\displaystyle\frac{b^2}{a+b}}{1-\left(\displaystyle\frac{a-b}{a+b}\right)^2}</math> | d) | <math>\displaystyle \frac{1}{1+\displaystyle \frac{1}{1+\displaystyle \frac{1}{1+x}}}</math> |